Question

Найти объем CO2 при сгорании 4 граммов С

Answer 1

С+ O2=CO2 n(C)= 4г/12г/моль=0,3моль. V(CO2)=0.3 моль * 22,4 л.моль = 6. 72 л.

Answer 2

Calculating the Volume of CO2 Produced from the Combustion of 4 Grams of Carbon

To calculate the volume of CO2 produced from the combustion of 4 grams of carbon, we can use the stoichiometry of the reaction. The balanced chemical equation for the combustion of carbon is:

C + O2 → CO2

From this equation, we can see that 1 mole of carbon reacts with 1 mole of oxygen to produce 1 mole of carbon dioxide.

The molar mass of carbon (C) is approximately 12.01 g/mol, and the molar mass of carbon dioxide (CO2) is approximately 44.01 g/mol.

Calculation

1. Convert grams of carbon to moles: - 4 grams of carbon is equal to 4/12.01 ≈ 0.333 moles of carbon.

2. Determine the moles of CO2 produced: - Since the stoichiometry of the reaction is 1:1, 0.333 moles of carbon will produce 0.333 moles of CO2.

3. Convert moles of CO2 to volume at standard conditions (0°C and 1 atm): - Using the ideal gas law, we can calculate the volume of CO2 produced. - The ideal gas law is given by the equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

- At standard conditions, 1 mole of any ideal gas occupies approximately 22.4 liters.

Conclusion

Therefore, the volume of CO2 produced from the combustion of 4 grams of carbon at standard conditions is approximately 0.333 * 22.4 = 7.47 liters.