Question

Сернистый газ (SO2) – газ с едким неприятным запахом, используется при дезинфекции зернохранилищ. Сера массой 64 г прореагировала с кислородом. При этом образовалось 128 г сернистого газа. Определите массу кислорода, который прореагировал с серой

Answer 1

128Г+64Г=64г О2-64 Г

Answer 2

Calculation of the Mass of Oxygen Reacted with Sulfur

To determine the mass of oxygen that reacted with sulfur, we can use the law of conservation of mass. According to this law, the total mass of the reactants must be equal to the total mass of the products in a chemical reaction.

Given: - Mass of sulfur (S) = 64 g - Mass of sulfur dioxide (SO2) formed = 128 g

We need to find the mass of oxygen (O) that reacted with sulfur.

Let's assume the mass of oxygen reacted is x grams.

According to the reaction: S + O2 → SO2

From the balanced chemical equation, we can see that 1 mole of sulfur reacts with 1 mole of oxygen to form 1 mole of sulfur dioxide.

The molar mass of sulfur (S) is 32 g/mol, and the molar mass of sulfur dioxide (SO2) is 64 g/mol.

Using the molar ratios, we can set up the following equation:

(64 g S) / (32 g/mol S) = (128 g SO2) / (64 g/mol SO2) = (x g O) / (32 g/mol O)

Simplifying the equation, we find:

2 mol S = 2 mol SO2 = 1 mol O

Therefore, the mass of oxygen that reacted with sulfur is equal to the molar mass of oxygen, which is 32 g/mol.

Hence, the mass of oxygen that reacted with sulfur is 32 grams.