Question

Схема щелочного гидролиза сложного эфира: 1)CH3-CH2-CH=CH2+KOH-----> 2)C15H31-COOK+H2O----> 3) CH3-COOCH3+KOH-----> 4) C15H31-COOH+KOH----->

Answer 1

СН3СООСН3+КОН⇒СН3СООК +СН3ОН

Answer 2

Scheme of Alkaline Hydrolysis of a Complex Ether:

The scheme you provided describes the alkaline hydrolysis of a complex ether. Let's break down the steps:

1) CH3-CH2-CH=CH2 + KOH -> 2) C15H31-COOK + H2O -> 3) CH3-COOCH3 + KOH -> 4) C15H31-COOH + KOH ->

Here's a detailed explanation of each step:

1) In the first step, the complex ether CH3-CH2-CH=CH2 reacts with KOH (potassium hydroxide). The reaction involves the breaking of the carbon-oxygen bond in the ether, resulting in the formation of an alkoxide ion and an alkene. The alkoxide ion is formed by the attack of the hydroxide ion (OH-) from KOH on the carbon atom bonded to the oxygen atom in the ether. The alkene formed in this step is CH3-CH2-CH=CH2.

2) In the second step, the alkoxide ion (C15H31-COOK) formed in the previous step reacts with water (H2O). This reaction is known as hydrolysis. The alkoxide ion reacts with water to form an alcohol (CH3-COOCH3) and a potassium hydroxide ion (KOH).

3) In the third step, the alcohol (CH3-COOCH3) formed in the previous step reacts with KOH. This reaction is also a hydrolysis reaction. The alcohol reacts with KOH to form a potassium alkoxide ion and an alcohol. The potassium alkoxide ion is CH3-COO-K.

4) In the fourth and final step, the potassium alkoxide ion (CH3-COO-K) formed in the previous step reacts with KOH. This reaction is another hydrolysis reaction. The potassium alkoxide ion reacts with KOH to form a carboxylic acid (C15H31-COOH) and a potassium hydroxide ion (KOH).

Please note that the scheme you provided is a simplified representation of the alkaline hydrolysis of a complex ether. The actual reaction may involve more complex molecules and intermediates.