Question

Определите степень окисления:XeF4Na2CrO4NH4ClO4BaMrO4 Пожалуйста помогите

Answer 1

Xe+4,F-1

Na+1,Cr+6,O-2

N+3,H+1,Cl+7,O-2

Ba+2,Mr+6,O-2

 

Answer 2

Determining Oxidation States

To determine the oxidation states of the elements in the given compounds, we can follow some general rules:

1. The oxidation state of an element in its elemental form is always 0. 2. The sum of the oxidation states of all the atoms in a compound is equal to the overall charge of the compound. 3. In compounds, the oxidation state of fluorine is always -1, and the oxidation state of oxygen is usually -2.

Let's apply these rules to the compounds provided:

1. XeF4: - Xenon (Xe) is a noble gas and typically has an oxidation state of 0. - Fluorine (F) has an oxidation state of -1. - Using the rule that the sum of oxidation states equals the overall charge, we can calculate the oxidation state of xenon.

2. Na2CrO4: - Sodium (Na) typically has an oxidation state of +1. - Oxygen (O) usually has an oxidation state of -2. - Using the rule that the sum of oxidation states equals the overall charge, we can calculate the oxidation state of chromium (Cr).

3. NH4ClO4: - Hydrogen (H) typically has an oxidation state of +1. - Chlorine (Cl) usually has an oxidation state of -1. - Oxygen (O) usually has an oxidation state of -2. - Using the rule that the sum of oxidation states equals the overall charge, we can calculate the oxidation state of nitrogen (N).

4. BaMrO4: - It seems there might be a typo in the compound "BaMrO4." It's possible that "Mr" is a typo and should be "Mn" for manganese. If that's the case, we can proceed with determining the oxidation state of manganese in BaMnO4.

Let's calculate the oxidation states for each of these compounds based on the rules mentioned above.