Question

Схеми реакцій у порядку збільшення загального числа прийнятих електоронів у рівняннях розмістяться в ряд А)SO2+O2=SO3 Б)PbO+C=Pb+CO В)MoO3+H2=Mo+H2O Г)Fe2O3+CO=Fe+CO2

Answer 1

А)SO2+O2=SO3
O₂⁰  + 4e = 2O⁻²
Б)PbO+C=Pb+CO
Pb⁺² +2e = Pb⁰
В)MoO3+H2=Mo+H2O
Mo⁺⁶ + 6e = Mo⁰
Г)Fe2O3+CO=Fe+CO2
Fe⁺³ +3e = Fe⁰
 ответ:
запишу буквы уравнений в ряд
Б ----> Г ----> А ----> В

Answer 2

Reaction Schemes in Increasing Order of Total Number of Electrons Accepted:

A) SO2 + O2 = SO3

The reaction involves the oxidation of sulfur dioxide (SO2) to sulfur trioxide (SO3) using oxygen (O2). This is a redox reaction where sulfur dioxide is oxidized and oxygen is reduced. The reaction scheme can be represented as follows:

2 SO2 + O2 → 2 SO3

B) PbO + C = Pb + CO

This reaction involves the reduction of lead oxide (PbO) using carbon (C) to produce lead (Pb) and carbon monoxide (CO). The reaction scheme can be represented as follows:

PbO + C → Pb + CO

C) MoO3 + H2 = Mo + H2O

This reaction involves the reduction of molybdenum trioxide (MoO3) using hydrogen gas (H2) to produce molybdenum (Mo) and water (H2O). The reaction scheme can be represented as follows:

MoO3 + 3 H2 → Mo + 3 H2O

Г) Fe2O3 + CO = Fe + CO2

This reaction involves the reduction of iron(III) oxide (Fe2O3) using carbon monoxide (CO) to produce iron (Fe) and carbon dioxide (CO2). The reaction scheme can be represented as follows:

Fe2O3 + 3 CO → 2 Fe + 3 CO2

Please note that the reactions mentioned above are balanced equations and represent the overall reaction schemes.