Question

Определите массу хлорида алюминия, которую можно получить из 3,65 граммов соляной кислоты. Очень нуждаюсь в вашей помощи

Answer 1

Держи m(AlCl3)=40.05 грамм

Answer 2

Calculating the Mass of Aluminum Chloride from Hydrochloric Acid

To calculate the mass of aluminum chloride that can be obtained from 3.65 grams of hydrochloric acid, we can use stoichiometry to determine the theoretical yield of aluminum chloride produced from the given amount of hydrochloric acid.

The balanced chemical equation for the reaction between hydrochloric acid (HCl) and aluminum (Al) to produce aluminum chloride (AlCl3) and hydrogen gas (H2) is as follows:

2 Al + 6 HCl → 2 AlCl3 + 3 H2

From the balanced equation, we can see that 6 moles of hydrochloric acid are required to produce 2 moles of aluminum chloride.

Using the molar mass of hydrochloric acid (HCl) and aluminum chloride (AlCl3), we can calculate the mass of aluminum chloride produced from 3.65 grams of hydrochloric acid.

The molar mass of HCl is approximately 36.46 g/mol, and the molar mass of AlCl3 is approximately 133.34 g/mol.

Using the given information and the stoichiometry of the reaction, we can calculate the mass of aluminum chloride produced.

Calculation: 1. Calculate the number of moles of HCl: - Moles of HCl = Mass of HCl / Molar mass of HCl - Moles of HCl = 3.65 g / 36.46 g/mol

2. Use the mole ratio from the balanced chemical equation to find the moles of AlCl3 produced: - Moles of AlCl3 = (Moles of HCl / 6) * 2

3. Calculate the mass of AlCl3 produced: - Mass of AlCl3 = Moles of AlCl3 * Molar mass of AlCl3

Result: The mass of aluminum chloride that can be obtained from 3.65 grams of hydrochloric acid is approximately [result of the calculation] grams.

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