Question

Вычислите относительные молекулярные массы веществ,формулы которых Fe3O4,C4H10,FeCO3,HNO3,NaOH,K2SO4.

Answer 1

Mr(Fe3O4) = 56*3+16*4 = 232
Mr(C4H10) = 12*4 + 1*10 = 58
Mr(FeCO3) = 56+12+16*3 = 116
Mr(HNO3) = 1+14+16*3 = 63
Mr(NaOH) = 23+16+1=40
Mr(K2SO4) = 39*2+32+16*4 = 174

Answer 2

Calculation of Relative Molecular Masses

To calculate the relative molecular masses of the given substances, we need to determine the atomic masses of the elements present in each compound and then sum them up according to the molecular formula.

1. Fe3O4 (Iron(II,III) oxide): - Atomic mass of Fe = 55.845 g/mol - Atomic mass of O = 15.999 g/mol - Relative molecular mass of Fe3O4 = (3 * 55.845) + (4 * 15.999) = 231.532 g/mol.

2. C4H10 (Butane): - Atomic mass of C = 12.011 g/mol - Atomic mass of H = 1.008 g/mol - Relative molecular mass of C4H10 = (4 * 12.011) + (10 * 1.008) = 58.124 g/mol.

3. FeCO3 (Iron(II) carbonate): - Atomic mass of Fe = 55.845 g/mol - Atomic mass of C = 12.011 g/mol - Atomic mass of O = 15.999 g/mol - Relative molecular mass of FeCO3 = 55.845 + 12.011 + (3 * 15.999) = 115.853 g/mol.

4. HNO3 (Nitric acid): - Atomic mass of H = 1.008 g/mol - Atomic mass of N = 14.007 g/mol - Atomic mass of O = 15.999 g/mol - Relative molecular mass of HNO3 = 1.008 + 14.007 + (3 * 15.999) = 63.012 g/mol.

5. NaOH (Sodium hydroxide): - Atomic mass of Na = 22.990 g/mol - Atomic mass of O = 15.999 g/mol - Atomic mass of H = 1.008 g/mol - Relative molecular mass of NaOH = 22.990 + 15.999 + 1.008 = 39.997 g/mol.

6. K2SO4 (Potassium sulfate): - Atomic mass of K = 39.098 g/mol - Atomic mass of S = 32.06 g/mol - Atomic mass of O = 15.999 g/mol - Relative molecular mass of K2SO4 = (2 * 39.098) + 32.06 + (4 * 15.999) = 174.259 g/mol.

Therefore, the relative molecular masses of the given substances are as follows: - Fe3O4: 231.532 g/mol - C4H10: 58.124 g/mol - FeCO3: 115.853 g/mol - HNO3: 63.012 g/mol - NaOH: 39.997 g/mol - K2SO4: 174.259 g/mol