Question

Какое количество вещества оксида алюминия AI(2)O(3) имеет массу 714 грамм.

Answer 1

оксид аллюминия колличеством 7 моль

Answer 2

Алюминия оксид колличиством 7 моль имеет такую массу.

Answer 3

Calculating the Amount of Substance of Aluminum Oxide (Al2O3)

To calculate the amount of substance of aluminum oxide (Al2O3) with a mass of 714 grams, we can use the molar mass of Al2O3 to convert the mass to moles.

The molar mass of Al2O3 can be calculated as follows: - Molar mass of Al = 26.98 g/mol - Molar mass of O = 16.00 g/mol - Molar mass of Al2O3 = (2 * molar mass of Al) + (3 * molar mass of O)

Molar mass of Al2O3 = (2 * 26.98 g/mol) + (3 * 16.00 g/mol)

Molar mass of Al2O3 = 53.96 g/mol + 48.00 g/mol

Molar mass of Al2O3 = 101.96 g/mol

Now, we can use the molar mass to calculate the amount of substance (moles) of Al2O3.

The amount of substance (moles) can be calculated using the formula: Amount of substance (moles) = Mass / Molar mass

Amount of substance (moles) = 714 g / 101.96 g/mol

Amount of substance (moles) ≈ 7 moles

Therefore, the amount of substance of aluminum oxide (Al2O3) with a mass of 714 grams is approximately 7 moles.