Question

6 KOH + Fe2(SO4)3 = 3 K2SO4 + 2 Fe(OH)3 2 KOH + SO3 = H2O + K2SO4 K2O + H2SO4 = H2P + K2SO4 K2O + Fe(SO4)3 = Fe2O3 + K2SO4 K2O + H2O = 2 KOH K2O + SO3 = K2SO4 сделать уравнения.

Answer 1

6 KOH + Fe2(SO4)3 = 3 K2SO4 + 2 Fe(OH)3 
2 KOH + SO3 = H2O + K2SO4 
K2O + H2SO4 = H2O + K2SO4 
K2O + Fe(SO4)3 = не идет
K2O +  H2O = 2 KOH 
K2O + SO3 = K2SO4

Answer 2

Balancing Chemical Equations

To balance the given chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance each equation step by step:

1. 6 KOH + Fe2(SO4)3 = 3 K2SO4 + 2 Fe(OH)3

To balance the equation, we start by balancing the Fe atoms. Since there are 2 Fe atoms on the left side and only 1 Fe atom on the right side, we need to put a coefficient of 2 in front of Fe(OH)3:

6 KOH + Fe2(SO4)3 = 3 K2SO4 + 2 Fe(OH)3

Next, let's balance the K atoms. There are 6 K atoms on the left side and 6 K atoms on the right side, so they are already balanced.

Finally, let's balance the O and H atoms. There are 18 O atoms on the left side (6 in KOH and 12 in Fe2(SO4)3) and 18 O atoms on the right side (6 in K2SO4 and 12 in Fe(OH)3). Similarly, there are 12 H atoms on the left side (6 in KOH) and 12 H atoms on the right side (6 in Fe(OH)3). Therefore, the equation is already balanced.

The balanced equation is:

6 KOH + Fe2(SO4)3 = 3 K2SO4 + 2 Fe(OH)3 2. 2 KOH + SO3 = H2O + K2SO4

To balance the equation, we start by balancing the K atoms. There are 2 K atoms on the left side and 2 K atoms on the right side, so they are already balanced.

Next, let's balance the O and H atoms. There are 3 O atoms on the left side (from SO3) and 1 O atom on the right side (from H2O). To balance the O atoms, we need to put a coefficient of 3 in front of H2O:

2 KOH + SO3 = 3 H2O + K2SO4

Finally, let's balance the H atoms. There are 2 H atoms on the left side (from 2 KOH) and 6 H atoms on the right side (from 3 H2O). To balance the H atoms, we need to put a coefficient of 3 in front of KOH:

3 KOH + SO3 = 3 H2O + K2SO4

The balanced equation is:

3 KOH + SO3 = 3 H2O + K2SO4 3. K2SO4 + K2O + H2SO4 = H2P + K2SO4 + K2O

To balance the equation, we start by balancing the K atoms. There are 4 K atoms on the left side and 4 K atoms on the right side, so they are already balanced.

Next, let's balance the O atoms. There are 4 O atoms on the left side (2 in K2SO4 and 2 in K2O) and 4 O atoms on the right side (2 in H2P and 2 in K2SO4). Therefore, the O atoms are already balanced.

Finally, let's balance the S and H atoms. There is 1 S atom on the left side (from H2SO4) and 1 S atom on the right side (from H2P). To balance the S atoms, we need to put a coefficient of 2 in front of H2P:

K2SO4 + K2O + H2SO4 = 2 H2P + K2SO4 + K2O

There are 4 H atoms on the left side (from 2 H2SO4) and 8 H atoms on the right side (from 4 H2P). To balance the H atoms, we need to put a coefficient of 4 in front of H2SO4:

K2SO4 + K2O + 4 H2SO4 = 2 H2P + K2SO4 + K2O

The balanced equation is:

K2SO4 + K2O + 4 H2SO4 = 2 H2P + K2SO4 + K2O 4. Fe(SO4)3 + K2SO4 + K2O + H2O = 2 KOH + K2SO4 + Fe2O3

To balance the equation, we start by balancing the Fe atoms. There is 1 Fe atom on the left side (from Fe(SO4)3) and 2 Fe atoms on the right side (from Fe2O3). To balance the Fe atoms, we need to put a coefficient of 2 in front of Fe(SO4)3:

2 Fe(SO4)3 + K2SO4 + K2O + H2O = 2 KOH + K2SO4 + Fe2O3

Next, let's balance the K atoms. There are 2 K atoms on the left side (from K2SO4) and 2 K atoms on the right side (from KOH and K2SO4). Therefore, the K atoms are already balanced.

Finally, let's balance the O and H atoms. There are 12 O atoms on the left side (from 3 SO4 groups in Fe(SO4)3 and 4 O atoms in H2O) and 12 O atoms on the right side (from 6 O atoms in KOH and 6 O atoms in Fe2O3). Similarly, there are 8 H atoms on the left side (from 4 H atoms in H2O) and 8 H atoms on the right side (from 8 H atoms in KOH). Therefore, the equation is already balanced.

The balanced equation is:

2 Fe(SO4)3 + K2SO4 + K2O + H2O = 2 KOH + K2SO4 + Fe2O3 5. K2SO4 + K2O + H2O = 2 KOH + K2O + SO3

To balance the equation, we start by balancing the K atoms. There are 4 K atoms on the left side and 4 K atoms on the right side, so they are already balanced.

Next, let's balance the O and H atoms. There are 4 O atoms on the left side (2 in K2SO4 and 2 in H2O) and 4 O atoms on the right side (2 in KOH and 2 in SO3). Similarly, there are 2 H atoms on the left side (from H2O) and 2 H atoms on the right side (from KOH). Therefore, the equation is already balanced.

The balanced equation is:

K2SO4 + K2O + H2O = 2 KOH + K2O + SO3 I hope this helps! Let me know if you have any further questions.