Вопрос задан 08.09.2018 в 23:18. Предмет Химия. Спрашивает Надеева Карина.

При взаимодействии 128 г меди с 32 г кислорода образовался оксид .определить его массу.

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Отвечает Александрова Таня.
Это скорей всего CuO=160г
Но это не точно
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of the Mass of the Oxide Formed

To determine the mass of the oxide formed when 128 g of copper (Cu) reacts with 32 g of oxygen (O), we need to consider the balanced chemical equation for the reaction between copper and oxygen.

The balanced chemical equation for the reaction is:

2Cu + O2 -> 2CuO

From the balanced equation, we can see that 2 moles of copper react with 1 mole of oxygen to form 2 moles of copper oxide.

To calculate the mass of the oxide formed, we can use the molar masses of copper (Cu) and oxygen (O) to convert the given masses into moles.

The molar mass of copper (Cu) is approximately 63.55 g/mol. The molar mass of oxygen (O) is approximately 16.00 g/mol.

Using these molar masses, we can calculate the number of moles of copper and oxygen:

Number of moles of copper (Cu) = Mass of copper (Cu) / Molar mass of copper (Cu) Number of moles of oxygen (O) = Mass of oxygen (O) / Molar mass of oxygen (O)

Substituting the given masses:

Number of moles of copper (Cu) = 128 g / 63.55 g/mol Number of moles of oxygen (O) = 32 g / 16.00 g/mol

Simplifying:

Number of moles of copper (Cu) = 2.01 mol Number of moles of oxygen (O) = 2.00 mol

Since the balanced equation shows that 2 moles of copper react with 1 mole of oxygen to form 2 moles of copper oxide, we can conclude that the number of moles of copper oxide formed is also 2.00 mol.

To calculate the mass of the oxide formed, we can use the equation:

Mass of the oxide formed = Number of moles of the oxide formed * Molar mass of the oxide

The molar mass of copper oxide (CuO) is approximately 79.55 g/mol.

Substituting the values:

Mass of the oxide formed = 2.00 mol * 79.55 g/mol

Calculating:

Mass of the oxide formed = 159.10 g

Therefore, when 128 g of copper reacts with 32 g of oxygen, approximately 159.10 g of copper oxide is formed.

Note: The calculated mass is an approximation and may vary slightly due to rounding errors.

Answer:

The mass of the oxide formed when 128 g of copper reacts with 32 g of oxygen is approximately 159.10 g.

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