Question

Составить РИО:1)Na+H3PO4=2)Cu+HCi=3)Zn+CuCi2=4)Ag+NaCi=

Answer 1

1. 6Na + 2H3PO4 = 2Na3PO4 + 3H2
6Na(0) + 6H(+) + 2PO4(3-) = 6Na(+) + 2PO4(3-) + 6H(0)
6Na(0) + 6H(+) = 6Na(+) + 6H(0)
2. Реакция невозможна, т.к. медь стоит до водорода в ряде напряжений металлов.
3. Zn + CuCl2 = ZnCl2 + Cu 
Zn(0) + Сu(2+) + 2Cl(-) = Zn(2+) + 2Cl(-) + Cu(0)
Zn(0) + Cu(2+) = Zn(2+) + Cu(0)
4. Реакция невозможна, менее активный металл не может вытеснить бoлее активный. 

Answer 2

1). 6Na + 2H3PO4 = 2Na3PO4 + 3H2 (стрелка вверх)
6Na(+) + 6H(+) + 2PO4(3-) = 6Na(+) + 2PO4(2-) + 3H2
6H(+) = 3H2(стрелка вверх)

Answer 3

Reaction 1: Na + H3PO4

The reaction between sodium (Na) and phosphoric acid (H3PO4) can be represented as follows:

Na + H3PO4 → NaH2PO4 + H2

In this reaction, sodium (Na) reacts with phosphoric acid (H3PO4) to form sodium dihydrogen phosphate (NaH2PO4) and hydrogen gas (H2).

Reaction 2: Cu + HCl

The reaction between copper (Cu) and hydrochloric acid (HCl) can be represented as follows:

Cu + 2HCl → CuCl2 + H2

In this reaction, copper (Cu) reacts with hydrochloric acid (HCl) to form copper(II) chloride (CuCl2) and hydrogen gas (H2).

Reaction 3: Zn + CuCl2

The reaction between zinc (Zn) and copper(II) chloride (CuCl2) can be represented as follows:

Zn + CuCl2 → ZnCl2 + Cu

In this reaction, zinc (Zn) reacts with copper(II) chloride (CuCl2) to form zinc chloride (ZnCl2) and copper (Cu).

Reaction 4: Ag + NaCl

The reaction between silver (Ag) and sodium chloride (NaCl) can be represented as follows:

Ag + NaCl → AgCl + Na

In this reaction, silver (Ag) reacts with sodium chloride (NaCl) to form silver chloride (AgCl) and sodium (Na).

Please note that these reactions are simplified representations and may not take into account specific conditions or stoichiometry.