Question

Вычислить объем углекислого газа который образуется при действии двухсотпятидесяти грамм раствора соляной кислоты на карбонат кальция

Answer 1

Я нехера не понял я это не прохадил

Answer 2

Calculating the volume of carbon dioxide gas formed

To calculate the volume of carbon dioxide gas formed when 250 grams of hydrochloric acid reacts with calcium carbonate, we first need to understand the chemical reaction:

CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)

This reaction shows that one mole of calcium carbonate will react with two moles of hydrochloric acid to produce one mole of carbon dioxide gas.

Using the molar masses: - Calcium carbonate (CaCO3): 100 g/mol - Hydrochloric acid (HCl): 36.5 g/mol - Carbon dioxide (CO2): 44 g/mol

We can calculate that: - 250 g of HCl contains 250/36.5 = 6.85 moles of HCl - Since the reaction ratio is 2 moles of HCl to 1 mole of CO2 produced, 6.85 moles of HCl will produce 6.85/2 = 3.425 moles of CO2 - Using the molar mass of CO2, 3.425 moles of CO2 is equivalent to 3.425 * 44 = 150.7 grams of CO2 - Using the gas law PV=nRT and standard temperature and pressure, 150.7 g of CO2 is equivalent to a volume of 150.7/44 = 3.42 liters of CO2 gas

Therefore, the volume of carbon dioxide gas produced from 250 grams of hydrochloric acid reacting with calcium carbonate is 3.42 liters.