Question

Рассчитайте количество и массу воды, образующейся при взаимодействии 2 моль водорода и 1 моль кислорода. Дано ли в условии избыточное количество какого-либо вещества?

Answer 1

O2 + 2H2 = 2H2O

n(H2) = n(O2) = 2 моль

m(H2O) = n(H2O) *M(H2O) = 2 моль * 18г/моль = 36г. 

Избыточных количеств не дано.

Answer 2

Calculation of the Amount and Mass of Water Formed

To calculate the amount and mass of water formed when 2 moles of hydrogen react with 1 mole of oxygen, we need to use the balanced chemical equation for the reaction:

2H₂ + O₂ → 2H₂O

From the balanced equation, we can see that 2 moles of hydrogen react with 1 mole of oxygen to form 2 moles of water. Therefore, the amount of water formed is 2 moles.

To calculate the mass of water formed, we need to know the molar mass of water, which is the sum of the molar masses of its constituent elements. The molar mass of hydrogen (H) is approximately 1 g/mol, and the molar mass of oxygen (O) is approximately 16 g/mol. The molar mass of water (H₂O) is then:

2(1 g/mol) + 16 g/mol = 18 g/mol

Since 2 moles of water are formed, the mass of water formed is:

2 moles × 18 g/mol = 36 g

Therefore, when 2 moles of hydrogen react with 1 mole of oxygen, 2 moles of water are formed with a mass of 36 grams.

Excess Reactant

The question does not provide information about whether there is an excess amount of any substance. Therefore, we cannot determine if there is an excess reactant based on the given information.

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