Question

По термохимическому уравнению реакцииCaCO3=CaO+CO2 - 180кДжрассчитайте количество теплоты и массу карбоната кальция,необходимые для получения 140 кг оксида кальция.Ставлю сразу как лучший.

Answer 1

 х кг           140кг            у кДж
СаСО3 = СаО + СО2 -180кДж 
100г          56г

х=100*140/56=250кг
у= 140*180/56=450кДж

Answer 2

Calculation of Heat and Mass for the Reaction CaCO3 = CaO + CO2

To calculate the amount of heat and mass required to obtain 140 kg of calcium oxide (CaO) from calcium carbonate (CaCO3) using the given thermochemical equation, we need to follow these steps:

1. Determine the molar mass of CaCO3 and CaO. 2. Calculate the moles of CaO required to obtain 140 kg. 3. Use the stoichiometric coefficients from the balanced equation to find the moles of CaCO3 required. 4. Calculate the mass of CaCO3 required. 5. Calculate the heat released during the reaction.

Let's go through each step in detail.

Step 1: Determine the Molar Mass

The molar mass of a compound is the sum of the atomic masses of all the atoms in the compound. The atomic masses of calcium (Ca), carbon (C), and oxygen (O) are approximately 40.08 g/mol, 12.01 g/mol, and 16.00 g/mol, respectively.

The molar mass of CaCO3 can be calculated as follows:

Molar mass of CaCO3 = (1 * molar mass of Ca) + (1 * molar mass of C) + (3 * molar mass of O)

Step 2: Calculate Moles of CaO

To calculate the moles of CaO required to obtain 140 kg, we need to use the molar mass of CaO.

Moles of CaO = Mass of CaO / Molar mass of CaO

Step 3: Use Stoichiometric Coefficients

The balanced equation for the reaction is:

CaCO3 = CaO + CO2

From the equation, we can see that 1 mole of CaCO3 produces 1 mole of CaO. Therefore, the moles of CaCO3 required will be the same as the moles of CaO.

Step 4: Calculate Mass of CaCO3

To calculate the mass of CaCO3 required, we can use the moles of CaCO3 obtained in Step 3 and the molar mass of CaCO3.

Mass of CaCO3 = Moles of CaCO3 * Molar mass of CaCO3

Step 5: Calculate Heat Released

The given thermochemical equation states that the reaction releases 180 kJ of heat. Since the reaction is exothermic, the heat released will be negative.

Heat released = -180 kJ

Now, let's perform the calculations.

Calculation:

Step 1: Molar mass of CaCO3: - Molar mass of Ca = 40.08 g/mol - Molar mass of C = 12.01 g/mol - Molar mass of O = 16.00 g/mol

Molar mass of CaCO3 = (1 * 40.08) + (1 * 12.01) + (3 * 16.00) g/mol

Step 2: Moles of CaO: - Mass of CaO = 140 kg - Molar mass of CaO = atomic mass of Ca + atomic mass of O

Moles of CaO = (140,000 g) / (molar mass of CaO) mol

Step 3: Moles of CaCO3: - Moles of CaCO3 = Moles of CaO

Step 4: Mass of CaCO3: - Mass of CaCO3 = Moles of CaCO3 * Molar mass of CaCO3

Step 5: Heat released: - Heat released = -180 kJ

Please note that the specific values for the molar mass of CaO and CaCO3 are not provided in the search results. To proceed with the calculation, we need the exact values for these molar masses.