Вопрос задан 17.08.2018 в 10:39. Предмет Химия. Спрашивает Sindukova Natasha.

Помогите сделать цепочкуCH4-HCOOH-CH3OH-CH3Cl-C2H6-C2H5OH-CH3COOH-CH4

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Отвечает Умеренков Никита.
CH4 + O2 → HCOH + H2O 
2HCHO + 2H2O→2CH3OH + O2 
CH3OH + HCl → CH3Cl + H2O 
CH3Cl + 2Na + CH3Cl → C2H6 + 2NaCl 
С2H6+H2O → C2H5OH+H2 
СН3СН2ОН + О2 → СН3СООН + Н2О 
CH3COOH + NaOH = CH4 + Na2CO3
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Chemical Reaction Chain:

CH4 - Methane HCOOH - Formic Acid CH3OH - Methanol CH3Cl - Methyl Chloride C2H6 - Ethane C2H5OH - Ethanol CH3COOH - Acetic Acid CH4 - Methane

The chemical reaction chain you provided can be explained as follows:

1. CH4 (Methane) can react with oxygen to produce CO2 (Carbon Dioxide) and H2O (Water). - Source: 2. HCOOH (Formic Acid) is not directly related to the previous compound in the chain, so it doesn't participate in a simple chemical reaction with CH4.

3. CH3OH (Methanol) can be produced from the reaction of carbon monoxide and hydrogen, and it can further react with oxygen to produce carbon dioxide and water.

4. CH3Cl (Methyl Chloride) can be produced from the reaction of methane and chlorine, and it can further react with other compounds to form different products.

5. C2H6 (Ethane) can react with oxygen to produce carbon dioxide and water. - Source: 6. C2H5OH (Ethanol) can be produced from the reaction of ethylene and water, and it can further react with oxygen to produce carbon dioxide and water.

7. CH3COOH (Acetic Acid) can be produced from the reaction of methanol and carbon monoxide, and it can further react with other compounds to form different products.

8. CH4 (Methane), as mentioned earlier, can react with oxygen to produce carbon dioxide and water.

It's important to note that the reactions of these compounds are influenced by various factors such as temperature, pressure, and the presence of catalysts. Additionally, the specific reactions involving these compounds can vary based on the conditions and reactants involved.

If you have any specific questions about the reactions or the properties of these compounds, feel free to ask!

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