Question

1)При горении на воздухе спирта С2Н6О и эфира С4Н10О образуются углекислый газ и вода.Напишите уравнения реакций.2)Напишите уравнение реакции горения безводной уксусной кислоты С4Н4О2,если известно,что продуктами являются вода и углекислый газ.

Answer 1

C4h10o+6o2=4co2+5h2o
C2H5OH+3O2=2CO2+3H2O
C3H7COOH+5O2=4CO2+4H2O

Answer 2

Combustion of Ethanol (C2H6O) and Ether (C4H10O)

The combustion of ethanol (C2H6O) and ether (C4H10O) in the presence of oxygen (O2) results in the formation of carbon dioxide (CO2) and water (H2O). The balanced chemical equations for these reactions are as follows:

1) Combustion of Ethanol (C2H6O): - Equation: C2H6O + 3O2 → 2CO2 + 3H2O [[1]] - This equation shows that one molecule of ethanol reacts with three molecules of oxygen to produce two molecules of carbon dioxide and three molecules of water.

2) Combustion of Ether (C4H10O): - Equation: C4H10O + 6O2 → 4CO2 + 5H2O [[2]] - This equation shows that one molecule of ether reacts with six molecules of oxygen to produce four molecules of carbon dioxide and five molecules of water.

Combustion of Anhydrous Acetic Acid (C4H4O2)

The combustion of anhydrous acetic acid (C4H4O2) in the presence of oxygen (O2) results in the formation of carbon dioxide (CO2) and water (H2O). The balanced chemical equation for this reaction is as follows:

3) Combustion of Anhydrous Acetic Acid (C4H4O2): - Equation: C4H4O2 + 6O2 → 4CO2 + 2H2O [[3]] - This equation shows that one molecule of anhydrous acetic acid reacts with six molecules of oxygen to produce four molecules of carbon dioxide and two molecules of water.

Please note that the equations provided are balanced chemical equations, which means that the number of atoms of each element is the same on both sides of the equation.