Question

Из 500л ацетилена получили бензол. расчитайте массу

Answer 1

0.5 л       х г
3C2H2=C6H6
3·22.4л   78 г
х=0.5·78÷67.2=0.58 г

Answer 2

Calculating the Mass of Benzene Produced from 500 L of Acetylene

To calculate the mass of benzene produced from 500 L of acetylene, we can use the following chemical equation for the conversion of acetylene to benzene:

2 C2H2 → C6H6

This equation shows that 2 moles of acetylene (C2H2) produce 1 mole of benzene (C6H6).

Step 1: Convert Volume of Acetylene to Moles

First, we need to convert the volume of acetylene to moles. The molar volume of a gas at standard temperature and pressure (STP) is 22.4 L/mol.

Using the given volume of acetylene (500 L), we can calculate the number of moles using the formula:

moles = volume (L) / molar volume (L/mol)

moles = 500 L / 22.4 L/mol

moles ≈ 22.32 mol

Step 2: Calculate the Mass of Benzene Produced

Now that we have the number of moles of acetylene, we can use the stoichiometry of the chemical equation to find the moles of benzene produced.

From the balanced chemical equation, we know that 2 moles of acetylene produce 1 mole of benzene.

So, the moles of benzene produced will be half the moles of acetylene:

moles of benzene = moles of acetylene / 2

moles of benzene ≈ 22.32 mol / 2

moles of benzene ≈ 11.16 mol

Step 3: Convert Moles to Mass

Finally, we can convert the moles of benzene to mass using the molar mass of benzene, which is approximately 78.11 g/mol.

Using the formula:

mass = moles × molar mass

mass ≈ 11.16 mol × 78.11 g/mol

mass ≈ 871.68 g

Therefore, the mass of benzene produced from 500 L of acetylene is approximately 871.68 grams.