Question

Оксид углерода(IV) имеет массу 154 г. Рассчитайте объём, который он займёт при нормальных условиях. Вычислите относительную плотность оксида углерода (IV) по водороду.

Answer 1

M=154 (г)

M(CO2)=12+2*16=44 (г/моль)
n=m/M=154/44=3.5 (моль)
V=Vm*n, где Vm - объем газа при н.у. = 22.4 (л/моль)
V=22.4*3.5=78.4 (л)

Answer 2

M(CO2) = 154 г
Mr(CO2) = 44 г/моль

V = n х Vm

n = m / Mr

n(CO2) = 154 / 44 = 3.5 моль

V(CO2) = 3.5 x 22.4 = 78.4 л

p = m / V
p(CO2) = 154 / 78.4 = 1.96 г/л
а вычислять плотность по водороду можно просто разделив плотность СO2 на Mr(H2) т.е. 2 , то получим = 0.98 г/л

Answer 3

Answer in detail. Carbon dioxide has a mass of 154 g. Calculate the volume it will occupy at normal conditions. Calculate the relative density of carbon dioxide (IV) by hydrogen.

To answer this question, I will use the information from the web search results that I found using the query you provided. Here is my answer:

The volume of a gas at normal conditions (0°C and 1 atm) can be calculated using the ideal gas law: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature. To find the number of moles, we need to divide the mass of the gas by its molar mass. The molar mass of carbon dioxide (CO2) is 44 g/mol, so the number of moles is 154 / 44 = 3.5 mol. The universal gas constant R is 0.0821 L atm / mol K, and the temperature T is 273 K (0°C). Plugging these values into the ideal gas law, we get:

V = nRT / P

V = 3.5 x 0.0821 x 273 / 1

V = 78.4 L

Therefore, the volume of carbon dioxide with a mass of 154 g at normal conditions is 78.4 liters.

The relative density of a gas is the ratio of its density to the density of another gas, usually hydrogen, at the same conditions. The density of a gas can be found by dividing its mass by its volume. The mass of carbon dioxide is 154 g, and the volume is 78.4 L, so the density is 154 / 78.4 = 1.96 g/L. The molar mass of hydrogen (H2) is 2 g/mol, so the density of hydrogen at normal conditions is 2 / 22.4 = 0.089 g/L, where 22.4 L is the molar volume of any gas at normal conditions. The relative density of carbon dioxide by hydrogen is then:

1.96 / 0.089 = 22

Therefore, the relative density of carbon dioxide (IV) by hydrogen is 22.