Question

При действии серной кислоты на 3,246 г смеси хлорида натрия с сульфатом натрия было получено 3,516 г сульфата натрия. Каков был состав (в граммах) исходной смеси?

Answer 1

правда, я не совсем уверена в способе решении задачи, возможен еще другой способ, проще.
 

Answer 2

Calculation of the Composition of the Initial Mixture

To determine the composition of the initial mixture, we need to calculate the amount of sodium chloride (NaCl) and sodium sulfate (Na2SO4) present in the mixture.

Given: - Mass of the mixture = 3,246 g - Mass of sodium sulfate obtained = 3,516 g

Let's assume the mass of sodium chloride in the mixture is x grams. Therefore, the mass of sodium sulfate in the mixture would be (3,246 - x) grams.

According to the reaction between sulfuric acid (H2SO4) and sodium chloride (NaCl), sodium sulfate (Na2SO4) is formed:

2NaCl + H2SO4 → Na2SO4 + 2HCl

From the balanced equation, we can see that 2 moles of sodium chloride react to form 1 mole of sodium sulfate. This means that the molar ratio of sodium chloride to sodium sulfate is 2:1.

To calculate the amount of sodium chloride and sodium sulfate in grams, we need to convert the given masses to moles using their respective molar masses.

The molar mass of sodium chloride (NaCl) is 58.44 g/mol, and the molar mass of sodium sulfate (Na2SO4) is 142.04 g/mol.

Let's calculate the moles of sodium sulfate obtained: Moles of sodium sulfate = Mass of sodium sulfate obtained / Molar mass of sodium sulfate Moles of sodium sulfate = 3,516 g / 142.04 g/mol

Now, since the molar ratio of sodium chloride to sodium sulfate is 2:1, we can write the following equation:

Moles of sodium chloride / 2 = Moles of sodium sulfate

Substituting the values, we can solve for the moles of sodium chloride: Moles of sodium chloride / 2 = 3,516 g / 142.04 g/mol

Simplifying the equation, we find: Moles of sodium chloride = (3,516 g / 142.04 g/mol) * 2

Now, we can calculate the mass of sodium chloride: Mass of sodium chloride = Moles of sodium chloride * Molar mass of sodium chloride

Finally, we can calculate the mass of sodium sulfate: Mass of sodium sulfate = Mass of the mixture - Mass of sodium chloride

Let's perform the calculations:

Molar mass of sodium chloride (NaCl) = 58.44 g/mol Molar mass of sodium sulfate (Na2SO4) = 142.04 g/mol

Moles of sodium sulfate = 3,516 g / 142.04 g/mol = 24.74 mol

Moles of sodium chloride = (24.74 mol * 2) / 2 = 24.74 mol

Mass of sodium chloride = 24.74 mol * 58.44 g/mol = 1,445.34 g

Mass of sodium sulfate = 3,246 g - 1,445.34 g = 1,800.66 g

Therefore, the composition of the initial mixture was approximately: - Sodium chloride: 1,445.34 grams - Sodium sulfate: 1,800.66 grams

Please