Вопрос задан 05.08.2018 в 17:03. Предмет Химия. Спрашивает Клиндухов Андрей.

При растворении 15 г смеси порошков магния и меди в разбавленной соляной кислоте выделилось 4,48л

газа. рассчитайте массы металлов в смеси
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Отвечает Арифов Семён.
Спайс готовишь?? Атата!
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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of Metal Masses in the Mixture

To calculate the masses of magnesium (Mg) and copper (Cu) in the mixture, we need to use the information provided about the volume of gas released during the reaction.

According to the given information, when 15 grams of the mixture of magnesium and copper powders is dissolved in diluted hydrochloric acid (HCl), 4.48 liters of gas is released.

To calculate the masses of the metals, we can use the stoichiometry of the reaction and the ideal gas law.

The balanced chemical equation for the reaction between magnesium (Mg) and hydrochloric acid (HCl) is:

Mg + 2HCl → MgCl2 + H2

From the equation, we can see that 1 mole of magnesium reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.

To calculate the moles of hydrogen gas produced, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas (in atm) - V is the volume of the gas (in liters) - n is the number of moles of the gas - R is the ideal gas constant (0.0821 L·atm/mol·K) - T is the temperature of the gas (in Kelvin)

Given that the volume of gas released is 4.48 liters, we can calculate the number of moles of hydrogen gas produced.

Now, let's calculate the moles of hydrogen gas produced using the ideal gas law equation:

n = PV / RT

Substituting the given values: - P = 1 atm (standard pressure) - V = 4.48 L - R = 0.0821 L·atm/mol·K - T = 273.15 K (standard temperature)

n = (1 atm) * (4.48 L) / (0.0821 L·atm/mol·K * 273.15 K)

Calculating this expression will give us the number of moles of hydrogen gas produced.

Next, we can use the stoichiometry of the balanced chemical equation to relate the moles of hydrogen gas to the moles of magnesium.

From the balanced equation, we know that 1 mole of magnesium reacts to produce 1 mole of hydrogen gas. Therefore, the number of moles of magnesium is equal to the number of moles of hydrogen gas produced.

Finally, we can calculate the masses of magnesium and copper in the mixture using their respective molar masses.

The molar mass of magnesium (Mg) is approximately 24.31 g/mol, and the molar mass of copper (Cu) is approximately 63.55 g/mol.

To calculate the mass of magnesium, we multiply the number of moles of magnesium by its molar mass:

Mass of Mg = Moles of Mg * Molar mass of Mg

Similarly, to calculate the mass of copper, we multiply the number of moles of copper by its molar mass:

Mass of Cu = Moles of Cu * Molar mass of Cu

By substituting the calculated values, we can determine the masses of magnesium and copper in the mixture.

Please note that without the exact molar ratio of magnesium to copper in the mixture, we cannot determine the exact masses of each metal. However, we can calculate the masses based on the assumption of a 1:1 molar ratio.

Let's perform the calculations:

1. Calculate the moles of hydrogen gas produced using the ideal gas law equation. 2. Calculate the moles of magnesium based on the stoichiometry of the balanced chemical equation. 3. Calculate the mass of magnesium using its molar mass. 4. Calculate the mass of copper using its molar mass.

Please wait a moment while I perform the calculations.

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