Question

ОВР 1)Fe+CuCl2= 2)(раствор)Fe+H2SO4= Помогите пожалуйста...

Answer 1

Fe + CuCl2 = FeCl2 + Cu

Fe(0)-2e = Fe(+2)     1    в-ль, ок-ие

CU(+2) +2e = Cu(0)  1   ок-ль, в-ие

2Fe +6 H2SO4 = Fe2(SO4)3 + 3SO2 + 6H2O

Fe(0)-3e = Fe(+3) 2  в-ль, ок-ие

S(+6)+2e = S(+4) 3  ок-ль, в-ие

Answer 2

Reaction 1: Fe + CuCl2

The reaction between iron (Fe) and copper chloride (CuCl2) can be represented as follows:

Fe + CuCl2 → FeCl2 + Cu

In this reaction, iron displaces copper from copper chloride, resulting in the formation of iron chloride (FeCl2) and copper (Cu).

Reaction 2: Fe + H2SO4

The reaction between iron (Fe) and sulfuric acid (H2SO4) can be represented as follows:

Fe + H2SO4 → FeSO4 + H2

In this reaction, iron reacts with sulfuric acid to form iron sulfate (FeSO4) and hydrogen gas (H2).

I hope this helps! Let me know if you have any further questions.