Question

Вычислите массу сульфита натрия, который потребуется для получения 11,2 (н.у.) оксида серы (4) Ребят помогитеее срочно, если можно распишите все решение

Answer 1

х моль                         0,5 моль

Na2SO3 = Na2O + SO3 (газ, стрелка вверх)

1 моль                        1 моль

Найдем химическое количество SO3

n = V/Vm

n(SO3) = 11,2 л / 22,4 л/моль = 0,5 моль

Составим пропорцию и по ней найдем химическое количество сульфита натрия

х = 0,5

1      1

х = 0,5 => n(Na2SO3) = 0,5 моль

m = n*M

M(Na2SO3) = 23*2 + 32 + 16*3 = 126 г/моль

m(Na2SO3) = 0,5 моль * 126 г/моль = 63 г

Ответ: 63 г

 

Посмотри в учебнике какой буквой у вас обозначается химическое количество вещества. Измеряется в моль. Там может обозначатся буквой n, а может и буквой v. Если буквой v, то вместо n пиши v.

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Answer 2

Calculating the Mass of Sodium Sulfite Required to Produce 11.2 moles of Sulfur Dioxide (SO2)

To calculate the mass of sodium sulfite (Na2SO3) required to produce 11.2 moles of sulfur dioxide (SO2), we can use stoichiometry, which involves using the balanced chemical equation to relate the moles of the reactants and products.

The balanced chemical equation for the reaction is: 2 Na2SO3 + 3 O2 → 2 Na2SO4 + 2 SO2

From the balanced equation, we can see that 2 moles of sodium sulfite react to produce 2 moles of sulfur dioxide.

Calculation Steps:

1. Determine the Molar Mass of Sodium Sulfite (Na2SO3): - The molar mass of sodium sulfite (Na2SO3) can be calculated by adding the atomic masses of its constituent elements. - The atomic masses are: Na (sodium) = 22.99 g/mol, S (sulfur) = 32.07 g/mol, and O (oxygen) = 16.00 g/mol. - Therefore, the molar mass of Na2SO3 = 2*22.99 + 32.07 + 3*16.00 = 126.05 g/mol.

2. Use the Molar Ratio to Calculate the Mass of Sodium Sulfite: - From the balanced chemical equation, we know that 2 moles of sodium sulfite produce 2 moles of sulfur dioxide. - Therefore, the molar ratio of Na2SO3 to SO2 is 2:2, or simply 1:1.

3. Calculate the Mass of Sodium Sulfite Required: - Given that 11.2 moles of sulfur dioxide (SO2) are produced, we can use the molar ratio to find the moles of sodium sulfite required. - Since the molar ratio of Na2SO3 to SO2 is 1:1, the moles of Na2SO3 required will also be 11.2 moles.

4. Convert Moles to Mass: - Finally, to find the mass of sodium sulfite required, we can use the molar mass of Na2SO3. - Mass = moles * molar mass = 11.2 moles * 126.05 g/mol = 1410.56 grams of sodium sulfite.

Therefore, to produce 11.2 moles of sulfur dioxide, approximately 1410.56 grams of sodium sulfite will be required.