Question

После пропускания через раствор гидроксида калия 4,48 л сернистого газа получили 252,8 г раствора сульфита калия. Вычислите массовую долю соли в полученном растворе. ОБЯЗАТЕЛЬНО ДАНО И РЕШЕНИЕ!!! СРОЧНО!!!!

Answer 1

N(SO2)=4,48л/22,4лмоль=0.2моль n(SO2)1:1n(K2SO3) m(K2SO3)=n*M=0,2моль*158гмоль=31.6г W(K2SO3)=31.6/252.8*100%=12.5%

Answer 2

Calculation of the Mass Fraction of Potassium Sulfite in the Solution

To calculate the mass fraction of potassium sulfite in the solution, we need to determine the amount of potassium sulfite present in the solution and divide it by the total mass of the solution.

Given: - Volume of sulfur dioxide gas (SO2) passed through potassium hydroxide (KOH) solution = 4.48 L - Mass of potassium sulfite (K2SO3) solution obtained = 252.8 g

To find the mass fraction of potassium sulfite, we can follow these steps:

1. Convert the volume of sulfur dioxide gas to moles using the ideal gas law. 2. Use the balanced chemical equation to determine the mole ratio between sulfur dioxide and potassium sulfite. 3. Convert the moles of potassium sulfite to grams. 4. Calculate the mass fraction of potassium sulfite.

Let's calculate the mass fraction of potassium sulfite step by step:

Step 1: Convert the volume of sulfur dioxide gas to moles

To convert the volume of sulfur dioxide gas to moles, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas (assumed to be constant) - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature in Kelvin

Since the pressure, temperature, and gas constant are not provided, we will assume standard conditions (1 atm and 273.15 K).

Using the ideal gas law equation, we can rearrange it to solve for the number of moles (n):

n = PV / RT

Assuming standard conditions, the ideal gas constant (R) is approximately 0.0821 L·atm/(mol·K).

Let's calculate the number of moles of sulfur dioxide gas:

n(SO2) = (P(SO2) * V(SO2)) / (R * T)

Since the pressure and temperature are not provided, we will assume standard conditions:

n(SO2) = (1 atm * 4.48 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

n(SO2) ≈ 0.204 mol

Step 2: Determine the mole ratio between sulfur dioxide and potassium sulfite

The balanced chemical equation for the reaction between sulfur dioxide and potassium hydroxide is:

SO2 + 2 KOH → K2SO3 + H2O

From the balanced equation, we can see that the mole ratio between sulfur dioxide (SO2) and potassium sulfite (K2SO3) is 1:1.

Step 3: Convert the moles of potassium sulfite to grams

Since the mole ratio between sulfur dioxide and potassium sulfite is 1:1, the number of moles of potassium sulfite is also approximately 0.204 mol.

To convert moles to grams, we need to multiply the number of moles by the molar mass of potassium sulfite (K2SO3).

The molar mass of K2SO3 can be calculated as follows: - Molar mass of K = 39.10 g/mol - Molar mass of S = 32.07 g/mol - Molar mass of O = 16.00 g/mol

Molar mass of K2SO3 = (2 * Molar mass of K) + Molar mass of S + (3 * Molar mass of O)

Molar mass of K2SO3 = (2 * 39.10 g/mol) + 32.07 g/mol + (3 * 16.00 g/mol)

Molar mass of K2SO3 ≈ 158.27 g/mol

Mass of potassium sulfite = n(K2SO3) * Molar mass of K2SO3

Mass of potassium sulfite ≈ 0.204 mol * 158.27 g/mol

Mass of potassium sulfite ≈ 32.29 g

Step 4: Calculate the mass fraction of potassium sulfite

The mass fraction of potassium sulfite can be calculated by dividing the mass of potassium sulfite by the total mass of the solution.

Mass fraction of potassium sulfite = (Mass of potassium sulfite) / (Mass of potassium sulfite solution)

Mass fraction of potassium sulfite = 32.29 g / 252.8 g

Mass fraction of potassium sulfite ≈ 0.1279

Therefore, the mass fraction of potassium sulfite in the obtained solution is approximately 0.1279.

Please note that the calculations provided are based on the given information and assumptions made.