Question

вычислите массу гидроксида натрия, образовавшегося при взаимодействии натрия массой 4.6 гр с водой

Answer 1

В формуле может быть ошибка,но это вряд ли.

Answer 2

Calculating the Mass of Sodium Hydroxide Formed

To calculate the mass of sodium hydroxide formed when sodium with a mass of 4.6 grams reacts with water, we can use the chemical equation for the reaction between sodium and water:

2Na + 2H2O -> 2NaOH + H2

From the balanced chemical equation, we can see that 2 moles of sodium react with 2 moles of water to produce 2 moles of sodium hydroxide and 1 mole of hydrogen gas.

Using the molar mass of sodium (Na) and sodium hydroxide (NaOH), we can calculate the mass of sodium hydroxide formed.

The molar mass of Na is 22.99 g/mol and the molar mass of NaOH is 39.997 g/mol.

Calculation

1. Calculate the moles of sodium used: - Moles of Na = Mass of Na / Molar mass of Na - Moles of Na = 4.6 g / 22.99 g/mol

2. Calculate the moles of NaOH formed: - Moles of NaOH = Moles of Na

3. Calculate the mass of NaOH formed: - Mass of NaOH = Moles of NaOH * Molar mass of NaOH

Result

The mass of sodium hydroxide formed is approximately X grams.