Question

Яка маса 3 моль амоніаку NH3?

Answer 1

 Дано
n(NH3)=3 моль
знайти 
m (NH3)-?   
розв"язання
m=n*M
n(NH3)=3 моль
M=14+3*1=17г/моль
m (NH3)=3 моль *17г/моль=51 г

Answer 2

I can help you with your question.

The mass of 3 moles of ammonia NH3 is calculated by multiplying the number of moles by the molar mass of ammonia. The molar mass of ammonia is 17 g/mol, which is the sum of the atomic masses of nitrogen (14 g/mol) and hydrogen (1 g/mol). Therefore, the mass of 3 moles of ammonia is:

$$m(NH3) = n(NH3) \times M(NH3)$$ $$m(NH3) = 3 \text{ mol} \times 17 \text{ g/mol}$$ $$m(NH3) = 51 \text{ g}$$

This answer is consistent with the web search results that I found , , and . You can check them for more details. I hope this helps.