Question

Визначити валентність елементів у сполуках: РН3, Р2О5, Н2S, SO2, SO3, FeO, HF, NH3, CH4, CO, CO2, CuO. СРОЧНО!!

Answer 1

Valency of Elements in Compounds

Let's determine the valency of the elements in the given compounds:

1. RN3: - The compound RN3 does not correspond to a known chemical compound. It seems there might be a typo in the compound name.

2. P2O5: - In P2O5, phosphorus has a valency of 5, and oxygen has a valency of 2. - Phosphorus (P) has a valency of 5, and oxygen (O) has a valency of 2 [[1]].

3. H2S: - In H2S, hydrogen has a valency of 1, and sulfur has a valency of 2. - Hydrogen (H) has a valency of 1, and sulfur (S) has a valency of 2 [[2]].

4. SO2: - In SO2, sulfur has a valency of 4, and oxygen has a valency of 2. - Sulfur (S) has a valency of 4, and oxygen (O) has a valency of 2 [[3]].

5. SO3: - In SO3, sulfur has a valency of 6, and oxygen has a valency of 2. - Sulfur (S) has a valency of 6, and oxygen (O) has a valency of 2 [[4]].

6. FeO: - In FeO, iron has a valency of 2, and oxygen has a valency of 2. - Iron (Fe) has a valency of 2, and oxygen (O) has a valency of 2 [[5]].

7. HF: - In HF, hydrogen has a valency of 1, and fluorine has a valency of 1. - Hydrogen (H) has a valency of 1, and fluorine (F) has a valency of 1 [[6]].

8. NH3: - In NH3, nitrogen has a valency of 3, and hydrogen has a valency of 1. - Nitrogen (N) has a valency of 3, and hydrogen (H) has a valency of 1 [[7]].

9. CH4: - In CH4, carbon has a valency of 4, and hydrogen has a valency of 1. - Carbon (C) has a valency of 4, and hydrogen (H) has a valency of 1 [[8]].

10. CO: - In CO, carbon has a valency of 2, and oxygen has a valency of 2. - Carbon (C) has a valency of 2, and oxygen (O) has a valency of 2 [[9]].

11. CO2: - In CO2, carbon has a valency of 4, and oxygen has a valency of 2. - Carbon (C) has a valency of 4, and oxygen (O) has a valency of 2 [[10]].

12. CuO: - In CuO, copper has a valency of 2, and oxygen has a valency of 2. - Copper (Cu) has a valency of 2, and oxygen (O) has a valency of 2 [[11]].

I hope this helps! If you have any more questions, feel free to ask.