Вопрос задан 27.11.2023 в 21:05. Предмет Химия. Спрашивает Андреева Кристина.

З допомогою графіка залежності обчисліть яку массу NaCl, NaNO3, Na2SO4 слід узяти для приготування

100г розчину, насиченого за температури 100°С. 2)До якої температури необхідно остудити розчин NaNO3 щоб половина солі випала в осад?​
0 0
Перейти к ответам

Ответы на вопрос

Внимание! Ответы на вопросы дают живые люди. Они могут содержать ошибочную информацию, заблуждения, а также ответы могут быть сгенерированы нейросетями. Будьте внимательны. Если вы уверены, что ответ неверный, нажмите кнопку "Пожаловаться" под ответом.
Отвечает Киров Дмитрий.

.............................



0 0
Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Calculation of Mass for Saturated Solution at 100°C

To calculate the mass of NaCl, NaNO3, and Na2SO4 required to prepare a 100g solution saturated at 100°C, we need to consider the solubility of each salt at that temperature. The solubility of a substance refers to the maximum amount of solute that can dissolve in a given amount of solvent at a specific temperature.

Let's start by looking at the solubility of each salt at 100°C:

- NaCl: The solubility of NaCl at 100°C is approximately 39.2 grams per 100 grams of water [[1]]. - NaNO3: The solubility of NaNO3 at 100°C is approximately 88.3 grams per 100 grams of water [[2]]. - Na2SO4: The solubility of Na2SO4 at 100°C is approximately 47.6 grams per 100 grams of water [[3]].

To determine the mass of each salt required to prepare a 100g saturated solution at 100°C, we can use the following formula:

Mass of salt = (Solubility of salt / 100) * Mass of water

Let's calculate the mass of each salt:

- For NaCl: - Mass of NaCl = (39.2 / 100) * 100 = 39.2 grams

- For NaNO3: - Mass of NaNO3 = (88.3 / 100) * 100 = 88.3 grams

- For Na2SO4: - Mass of Na2SO4 = (47.6 / 100) * 100 = 47.6 grams

Therefore, to prepare a 100g solution saturated at 100°C, you would need approximately: - 39.2 grams of NaCl - 88.3 grams of NaNO3 - 47.6 grams of Na2SO4

Cooling Temperature for NaNO3 Solution Precipitation

To determine the temperature at which half of the NaNO3 salt will precipitate from the solution, we need to consider the solubility of NaNO3 at different temperatures.

The solubility of NaNO3 decreases as the temperature decreases. At a certain temperature, called the saturation temperature, the solution becomes saturated, and any further decrease in temperature will cause the excess salt to precipitate.

Unfortunately, the specific saturation temperature for NaNO3 is not provided in the search results. To accurately determine the temperature at which half of the NaNO3 salt will precipitate, we would need the solubility data at different temperatures.

However, we can make a general observation that as the temperature decreases, the solubility of NaNO3 decreases. Therefore, to precipitate half of the NaNO3 salt, you would need to cool the solution to a temperature below its saturation temperature.

Please note that without the specific solubility data at different temperatures, we cannot provide an exact temperature at which half of the NaNO3 salt will precipitate.

0 0

Похожие вопросы

Топ вопросов за вчера в категории Химия

Последние заданные вопросы в категории Химия

Задать вопрос