Question

Склади рівняння реакцій, добери коефіцієнти (у дужках указано валентність елементів в одержаних сполуках) __АІ + __О2= __С(ІV)+ __O2= __S(IV) + __O2=

Answer 1

4Al + 3O2 --> 2Al2O3

C + O2 --> CO2

S + O2 --> SO2

Answer 2

Balancing Chemical Equations

To balance the chemical equations provided, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance each equation step by step:

1. Equation: АІ + О2 = С(ІV) + O2

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides. Let's start with the elements that appear in multiple compounds:

- Oxygen (O): There are two oxygen atoms on the left side and four oxygen atoms on the right side. To balance the oxygen atoms, we need to put a coefficient of 2 in front of the oxygen molecule (O2) on the left side:

2АІ + 2О2 = С(ІV) + O2

Now, let's balance the other elements:

- АІ: There are two АІ atoms on the left side and one on the right side. To balance the АІ atoms, we need to put a coefficient of 2 in front of АІ on the right side:

2АІ + 2О2 = 2С(ІV) + O2

- С(ІV): There are no С(ІV) atoms on the left side and two on the right side. To balance the С(ІV) atoms, we need to put a coefficient of 2 in front of С(ІV) on the left side:

2АІ + 2О2 = 2С(ІV) + O2

The balanced equation is: 2АІ + 2О2 = 2С(ІV) + O2.

2. Equation: О2 = S(IV) + O2

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides. Let's start with the elements that appear in multiple compounds:

- Oxygen (O): There are two oxygen atoms on the left side and three oxygen atoms on the right side. To balance the oxygen atoms, we need to put a coefficient of 3 in front of the oxygen molecule (O2) on the left side:

3О2 = S(IV) + O2

Now, let's balance the other elements:

- S(IV): There are no S(IV) atoms on the left side and one on the right side. To balance the S(IV) atoms, we need to put a coefficient of 3 in front of S(IV) on the left side:

3О2 = 3S(IV) + O2

The balanced equation is: 3О2 = 3S(IV) + O2.

Please note that the valence states of the elements (ІV and IV) are not directly related to the balancing of the equations. The balancing process focuses on the number of atoms of each element on both sides of the equation.