Question

Визначте рівняння хімічної реакції, що характеризує одну із хімічних властивостей нерозчинних основ. Напишіть яку саме властивість вона характеризує: А)CuSO4+2KOH=Cu(OH)2+K2SO4 Б)Cu(OH)2+Mg=Mg(OH)2+Cu В)Mg(OH)2+2NaCl=MgCl2+2NaOH Г)2Fe(OH)3=Fe2O3+3H2O

Answer 1

Ответ:

C) Mg(OH)2 + 2NaCl = MgCl2 + 2NaOH

Объяснение:

Это уравнение химической реакции характеризует растворение нерастворимого основания (Mg(OH)2) в кислоте (HCl), при котором образуется растворимая соль (MgCl2) и растворимое основание (NaOH).

Answer 2

Equation for a Chemical Reaction Characterizing a Property of Insoluble Bases

One of the chemical properties of insoluble bases is their ability to undergo a precipitation reaction when reacted with certain compounds. A precipitation reaction occurs when two aqueous solutions are mixed, resulting in the formation of an insoluble solid called a precipitate.

The equation that characterizes this property for one of the insoluble bases is:

A) CuSO4 + 2KOH = Cu(OH)2 + K2SO4

This equation represents the reaction between copper(II) sulfate (CuSO4) and potassium hydroxide (KOH). When these two compounds are mixed, they react to form copper(II) hydroxide (Cu(OH)2) and potassium sulfate (K2SO4). Copper(II) hydroxide is insoluble in water and therefore precipitates out of the solution.

The property that this equation characterizes is the formation of an insoluble precipitate when an insoluble base reacts with a soluble compound. In this case, the insoluble base is copper(II) hydroxide (Cu(OH)2), which precipitates out of the solution.

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