Question

3.Здійснити перетворення: Na → Na 2 O →NaOH K → K 2 O →KOH Ba → BaO →Ba(OH) 2 S → SO 2 →H 2 SO 3 P → P 2 O 5 →H 3 PO 4

Answer 1

Ответ:

1. 2Na+2H2O=2Na2O+2H2

Na2O+H2O=2NaOH

2. 2K+2H2O=2K2O+2H2

K2O+H2O=KOH

3. 2Ba+O2=2BaO

BaO+2KOH=Ba(OH)2+K2O

4. S + O2= SO2 ( 4-ая валентность серы )

SO2+H2O=H2SO3

5. 4P+5O2=2P2O5 ( 5-ая валентность фосфора )

P2O5+3H2O=2H3PO4

Answer 2

Transformation of Elements:

The given chemical transformations involve the conversion of various elements into different compounds. Let's break down each transformation step by step:

1. Na → Na2O → NaOH: - Sodium (Na) reacts with oxygen (O) to form sodium oxide (Na2O) [[1]]. - Sodium oxide (Na2O) reacts with water (H2O) to produce sodium hydroxide (NaOH) [[2]].

2. K → K2O → KOH: - Potassium (K) reacts with oxygen (O) to form potassium oxide (K2O) [[3]]. - Potassium oxide (K2O) reacts with water (H2O) to produce potassium hydroxide (KOH) [[4]].

3. Ba → BaO → Ba(OH)2: - Barium (Ba) reacts with oxygen (O) to form barium oxide (BaO) [[5]]. - Barium oxide (BaO) reacts with water (H2O) to produce barium hydroxide (Ba(OH)2) [[6]].

4. S → SO2 → H2SO3: - Sulfur (S) reacts with oxygen (O) to form sulfur dioxide (SO2) [[7]]. - Sulfur dioxide (SO2) dissolves in water (H2O) to produce sulfurous acid (H2SO3) [[8]].

5. P → P2O5 → H3PO4: - Phosphorus (P) reacts with oxygen (O) to form phosphorus pentoxide (P2O5) [[9]]. - Phosphorus pentoxide (P2O5) reacts with water (H2O) to produce phosphoric acid (H3PO4) [[10]].

Please note that these transformations represent chemical reactions involving the elements and compounds mentioned.