Question

Обчислити об'єм оксиду карбону , та масу солі , що утвориться при дії на барій карбонат 64г 26% розчину соляної кислоти ( н.у.)

Answer 1

Дано:
m(р-ну ВаСО3)=64г
w(ВаСО3)=26%
V(СО2)-?
m(ВаСl2)-?
знаходимо масу речовини барія карбоната в 26% розчині: 64г*0,26=16,64г
16,64г                    Хг                    Хл
ВаСО3 + 2НСl = BaCl2 +H2O + CO2
197г                      208г                 22,4л

х=16,64*208/197=17,56г - масса солі барія хлорида
х=16,64*22,4/197=1.89л обєм вуглекислого газу

Answer 2

Calculating the Volume of Carbon Dioxide

To calculate the volume of carbon dioxide, we can use the ideal gas law equation:

V = (nRT)/P

Where: - V = volume of the gas - n = number of moles of the gas - R = ideal gas constant - T = temperature in Kelvin - P = pressure

Given that the conditions are not specified, we'll assume standard temperature and pressure (STP) for simplicity: - T = 273 K - P = 1 atm - R = 0.0821 L·atm/(K·mol) (ideal gas constant)

First, we need to calculate the number of moles of carbon dioxide using the given mass and molar mass of carbon dioxide.

The molar mass of carbon dioxide (CO2) is 44.01 g/mol.

Number of moles (n) = mass / molar mass

Number of moles (n) = 64 g / 44.01 g/mol

Number of moles (n) ≈ 1.454 moles

Now, we can use the ideal gas law to calculate the volume of carbon dioxide:

V = (1.454 moles * 0.0821 L·atm/(K·mol) * 273 K) / 1 atm

V ≈ 33.6 L

So, the volume of carbon dioxide formed is approximately 33.6 liters.

Calculating the Mass of Barium Chloride

The reaction between barium carbonate (BaCO3) and hydrochloric acid (HCl) can be represented as:

BaCO3 + 2HCl → BaCl2 + CO2 + H2O

From the balanced chemical equation, we can see that 1 mole of barium carbonate reacts with 2 moles of hydrochloric acid to produce 1 mole of barium chloride.

Given that the molar mass of barium carbonate (BaCO3) is 197.34 g/mol and the molar mass of barium chloride (BaCl2) is 208.23 g/mol, we can calculate the mass of barium chloride formed.

Number of moles of barium carbonate = mass / molar mass

Number of moles of barium carbonate = 64 g / 197.34 g/mol

Number of moles of barium carbonate ≈ 0.324 moles

Since the molar ratio of barium carbonate to barium chloride is 1:1, the number of moles of barium chloride formed is also approximately 0.324 moles.

Mass of barium chloride = number of moles * molar mass

Mass of barium chloride = 0.324 moles * 208.23 g/mol

Mass of barium chloride ≈ 67.5 g

So, the mass of barium chloride formed is approximately 67.5 grams.