Question

Розташуйте формули основ у порядку збільшенн їхньої молярної маси: A )CSOH Б )NaOH B )Mg(OH)2 Г) RbOH

Answer 1

Ответ:

1. б)

2. в)

3. г)

4. а)

Объяснение:

б) 39,997 г/моль

в) 58,319 г/моль

г) 102, 475 г/моль

а) 149, 912 г/моль

Бажаю успіхів :)

Answer 2

A) CSOH B) NaOH C) RbOH D) Mg(OH)2

To arrange the formulas in order of increasing molar mass, we need to determine the molar mass of each compound.

A) CSOH: C = 12.01 g/mol S = 32.07 g/mol O = 16.00 g/mol H = 1.01 g/mol

Molar mass of CSOH = 12.01 + 32.07 + 16.00 + 1.01 = 61.09 g/mol

B) NaOH: Na = 22.99 g/mol O = 16.00 g/mol H = 1.01 g/mol

Molar mass of NaOH = 22.99 + 16.00 + 1.01 = 40.00 g/mol

C) RbOH: Rb = 85.47 g/mol O = 16.00 g/mol H = 1.01 g/mol

Molar mass of RbOH = 85.47 + 16.00 + 1.01 = 102.48 g/mol

D) Mg(OH)2: Mg = 24.31 g/mol O = 16.00 g/mol H = 1.01 g/mol

Molar mass of Mg(OH)2 = (24.31 + (16.00 x 2)) + (1.01 x 2) = 58.33 g/mol

Arranging the formulas in order of increasing molar mass, we have: B) NaOH (40.00 g/mol) A) CSOH (61.09 g/mol) D) Mg(OH)2 (58.33 g/mol) C) RbOH (102.48 g/mol)