Question

Вычислить массу соли образовавшиеся при взаимодействии 16 г. гидроксида натрия в избытке серной кислоты.

Answer 1

2NaOH+H2SO4=NaSO4+2H2O

   0,4                                        0,4

n=16/40=0,4моль

m=0.4*142=56.8

Answer 2

2NaOH+H2SO4=Na2SO4+2H2O 

1)n(NaOH)=m/M=16/40=0,4 моль

2)n(Na2SO4)=   0,4/2=X/1  X=0,2 моль

3)m(Na2SO4)=n*M=0,2*142=28,4 г

Ответ:m(Na2SO4)=28,4 г

Answer 3

Calculation of the Mass of Salt Formed

To calculate the mass of salt formed during the reaction between 16 g of sodium hydroxide and an excess of sulfuric acid, we need to determine the balanced chemical equation for the reaction. The balanced equation will give us the stoichiometric ratio between the reactants and products, allowing us to calculate the mass of the salt formed.

The balanced chemical equation for the reaction between sodium hydroxide (NaOH) and sulfuric acid (H2SO4) is as follows:

2 NaOH + H2SO4 -> Na2SO4 + 2 H2O

From the balanced equation, we can see that 2 moles of sodium hydroxide react with 1 mole of sulfuric acid to produce 1 mole of sodium sulfate and 2 moles of water.

To calculate the mass of sodium sulfate formed, we need to convert the given mass of sodium hydroxide (16 g) to moles. The molar mass of sodium hydroxide (NaOH) is 40 g/mol (22.99 g/mol for sodium + 16.00 g/mol for oxygen + 1.01 g/mol for hydrogen).

Using the formula:

Number of moles = Mass / Molar mass

We can calculate the number of moles of sodium hydroxide:

Number of moles of NaOH = 16 g / 40 g/mol = 0.4 mol

According to the balanced equation, 2 moles of sodium hydroxide react to form 1 mole of sodium sulfate. Therefore, the number of moles of sodium sulfate formed is half the number of moles of sodium hydroxide:

Number of moles of Na2SO4 = 0.4 mol / 2 = 0.2 mol

To calculate the mass of sodium sulfate formed, we multiply the number of moles by the molar mass of sodium sulfate (142.04 g/mol):

Mass of Na2SO4 = 0.2 mol * 142.04 g/mol = 28.408 g

Therefore, the mass of salt (sodium sulfate) formed during the reaction is approximately 28.408 grams.

Please note that the calculated mass is an approximation and may vary slightly due to rounding errors.