Question

Определите молярную массу газовой смеси, состоящей из 2,24 л азота и 4,48 л водорода (н.у.)

Answer 1

Ответ:

Объяснение:

Смесь состоит из 2,24/22,4=0,1 моля азота и 4,48/22,4=0,2 моля водорода Молярная масса смеси = (0,1*28+0,2*2)/0,3=10,67.

Answer 2

Calculation of Molar Mass of Gas Mixture

To calculate the molar mass of a gas mixture, we need to know the molar masses of the individual gases in the mixture. The molar mass of a gas is the mass of one mole of that gas.

Let's calculate the molar mass of the given gas mixture, which consists of 2.24 L of nitrogen and 4.48 L of hydrogen at standard temperature and pressure (n.u.).

1. Calculate the number of moles of nitrogen: - The volume of nitrogen is given as 2.24 L. - The molar volume of an ideal gas at standard temperature and pressure (STP) is 22.4 L/mol. - Therefore, the number of moles of nitrogen can be calculated as: moles of nitrogen = volume of nitrogen / molar volume at STP. - Substituting the given values, we have: moles of nitrogen = 2.24 L / 22.4 L/mol.

2. Calculate the number of moles of hydrogen: - The volume of hydrogen is given as 4.48 L. - Using the same molar volume at STP, we can calculate the number of moles of hydrogen as: moles of hydrogen = volume of hydrogen / molar volume at STP. - Substituting the given values, we have: moles of hydrogen = 4.48 L / 22.4 L/mol.

3. Calculate the molar mass of the gas mixture: - The molar mass of a gas mixture is the sum of the products