Question

Допоможіть............ Скласти молекулярне, повне та скорочене йонні рівняння взаємодії: а) сульфатної кислоти з літій гідроксидом (не розкладаємо на йони воду); б) Ферум(III) хлорид з калій гідроксидом. ​

Answer 1

Ответ:

а) Сульфатна кислота з літій гідроксидом:

   Молекулярне рівняння:

   H2SO4+2LiOH→Li2SO4+2H2OH2​SO4​+2LiOH→Li2​SO4​+2H2​O

   Повне іонне рівняння:

   2H++SO42−+2Li++2OH−→2Li++SO42−+2H2O2H++SO42−​+2Li++2OH−→2Li++SO42−​+2H2​O

   Скорочене іонне рівняння:

   2H++2OH−→2H2O2H++2OH−→2H2​O

б) Ферум(III) хлорид з калій гідроксидом:

   Молекулярне рівняння:

   FeCl3+3KOH→Fe(OH)3+3KClFeCl3​+3KOH→Fe(OH)3​+3KCl

   Повне іонне рівняння:

   Fe3++3Cl−+3K++3OH−→Fe(OH)3+3K++3Cl−Fe3++3Cl−+3K++3OH−→Fe(OH)3​+3K++3Cl−

   Скорочене іонне рівняння:

   Fe3++3OH−→Fe(OH)3Fe3++3OH−→Fe(OH)3​

Объяснение:

Answer 2

Molecular Equations for the Interaction of Sulfuric Acid with Lithium Hydroxide

The molecular equation for the interaction of sulfuric acid (H2SO4) with lithium hydroxide (LiOH) can be written as follows:

a) Sulfuric Acid (H2SO4) + Lithium Hydroxide (LiOH) → Lithium Sulfate (Li2SO4) + Water (H2O)

This equation represents the reaction between one molecule of sulfuric acid and two molecules of lithium hydroxide, resulting in the formation of two molecules of lithium sulfate and two molecules of water.

Ionic Equations for the Interaction of Sulfuric Acid with Lithium Hydroxide

To write the ionic equation, we need to break down the reactants and products into their respective ions. Sulfuric acid dissociates into two hydrogen ions (H+) and one sulfate ion (SO4^2-), while lithium hydroxide dissociates into one lithium ion (Li+) and one hydroxide ion (OH-).

The ionic equation for the interaction of sulfuric acid with lithium hydroxide can be written as follows:

a) 2H+ (aq) + SO4^2- (aq) + 2Li+ (aq) + 2OH- (aq) → 2Li+ (aq) + SO4^2- (aq) + 2H2O (l)

This equation represents the reaction between two hydrogen ions, one sulfate ion, two lithium ions, and two hydroxide ions, resulting in the formation of two lithium ions, one sulfate ion, and two water molecules.

Molecular Equations for the Interaction of Iron(III) Chloride with Potassium Hydroxide

The molecular equation for the interaction of iron(III) chloride (FeCl3) with potassium hydroxide (KOH) can be written as follows:

b) Iron(III) Chloride (FeCl3) + Potassium Hydroxide (KOH) → Iron(III) Hydroxide (Fe(OH)3) + Potassium Chloride (KCl)

This equation represents the reaction between one molecule of iron(III) chloride and three molecules of potassium hydroxide, resulting in the formation of one molecule of iron(III) hydroxide and three molecules of potassium chloride.

Ionic Equations for the Interaction of Iron(III) Chloride with Potassium Hydroxide

To write the ionic equation, we need to break down the reactants and products into their respective ions. Iron(III) chloride dissociates into one iron(III) ion (Fe^3+) and three chloride ions (Cl-), while potassium hydroxide dissociates into one potassium ion (K+) and one hydroxide ion (OH-).

The ionic equation for the interaction of iron(III) chloride with potassium hydroxide can be written as follows:

b) Fe^3+ (aq) + 3Cl- (aq) + 3K+ (aq) + 3OH- (aq) → Fe(OH)3 (s) + 3K+ (aq) + 3Cl- (aq)

This equation represents the reaction between one iron(III) ion, three chloride ions, three potassium ions, and three hydroxide ions, resulting in the formation of one solid iron(III) hydroxide and three molecules of potassium chloride.

Please note that the equations provided are simplified representations of the reactions and may not account for all possible species present in the solution.