Question

ПОМОГИТЕ, ПОЖАЛУЙСТА! Какой объём (н.у) займет кислород, полученный при разложении 303 г нитрата калия?

Answer 1

303 x= 33,6 л
2 KNO3 = 2KNO2 + O2
202 22,4

Answer 2

Calculating the Volume of Oxygen Produced from the Decomposition of Potassium Nitrate

To calculate the volume of oxygen produced from the decomposition of potassium nitrate, we can use the ideal gas law equation, which relates the pressure, volume, amount of substance, and temperature of a gas. The equation is given by:

PV = nRT

Where: - P = pressure - V = volume - n = amount of substance (in moles) - R = ideal gas constant - T = temperature

We can use this equation to find the volume of oxygen produced when 303 grams of potassium nitrate decomposes.

Steps to Calculate the Volume of Oxygen Produced

1. Determine the Chemical Equation for the Decomposition of Potassium Nitrate: The decomposition of potassium nitrate can be represented by the following chemical equation: ``` 2 KNO3(s) → 2 KNO2(s) + O2(g) ```

2. Calculate the Moles of Oxygen Produced: From the balanced chemical equation, we can see that 2 moles of potassium nitrate produce 1 mole of oxygen gas. We need to convert the given mass of potassium nitrate to moles and then use the mole ratio to find the moles of oxygen produced.

3. Apply the Ideal Gas Law Equation: Once we have the moles of oxygen produced, we can use the ideal gas law equation to calculate the volume of oxygen at standard temperature and pressure (STP).

Conclusion

By following these steps, we can determine the volume of oxygen produced from the decomposition of 303 grams of potassium nitrate.

Let's proceed with the calculations.