Question

Калій гідроксид кількістю речовини 3 моль розчинили в 232 г води. Обчисліть масову частку розчиненої речовини в розчині.

Answer 1

Відповідь:

M(KOH)=56г/моль

m(KOH)=3*56=198г

m(розчину)=232+198=430г

w=198*100/430=46,04%

Пояснення:

Answer 2

To calculate the mass fraction of the dissolved substance in the solution, we need to know the molar mass of potassium hydroxide (KOH). The molar mass of KOH is approximately 56.11 g/mol.

Given that 3 moles of potassium hydroxide were dissolved in 232 g of water, we can calculate the mass of the dissolved substance using the following equation:

Mass of dissolved substance = Number of moles × Molar mass

Substituting the values into the equation:

Mass of dissolved substance = 3 moles × 56.11 g/mol = 168.33 g

To calculate the mass fraction, we divide the mass of the dissolved substance by the total mass of the solution (water + dissolved substance) and multiply by 100:

Mass fraction = (Mass of dissolved substance / Total mass of solution) × 100

Substituting the values into the equation:

Mass fraction = (168.33 g / (168.33 g + 232 g)) × 100 ≈ 42.05%

Therefore, the mass fraction of the dissolved substance (potassium hydroxide) in the solution is approximately 42.05%.

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