Question

Помогите с электроном балансом- AlBr3+Cl2=AlCl3+Br2, H2+Fe2O3=fe+H2O, H2S+o2=SO2+H2O, H2S+O2=S+H2O,H3N+O2+N2+H2O, H3N+O2=NO+H2O

Answer 1

2AlBr3+3Cl=2AlCl3+Br2
3H2+Fe2O3=2Fe+3H2O
2H2S+3O2=2SO2+2H2O
2H2S+O2=2S+2H2O 
4H3N+3O2=2N2+6H2O
4H3N+5O2=4NO+6H2O

Answer 2

2AlBr₃+3Cl₂=2AlCl₃+3Br₂
3H₂+Fe₂O₃=2Fe+3H₂O
2H₂S+3O₂=2SO₂+2H₂O
2H₂S+O₂=2S+2H₂O
4H₃N+3O₂=2N₂+6H₂O
4H₃N+5O₂=4NO+6H₂O

Answer 3

Balancing Chemical Equations

Let's balance the given chemical equations one by one.

1. AlBr3 + Cl2 = AlCl3 + Br2

To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

We start by counting the number of atoms for each element on both sides of the equation:

Al: 1 on the left, 1 on the right Br: 3 on the left, 2 on the right Cl: 2 on the left, 3 on the right

To balance the bromine (Br) atoms, we can place a coefficient of 2 in front of AlBr3 and a coefficient of 3 in front of Br2:

2 AlBr3 + 3 Cl2 = AlCl3 + 3 Br2

Now, the equation is balanced with respect to bromine. However, the chlorine (Cl) atoms are not balanced. To balance them, we can place a coefficient of 2 in front of AlCl3:

2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2

Now, the equation is balanced with respect to both bromine and chlorine.

2. H2 Fe2O3 = Fe + H2O

Let's count the number of atoms for each element on both sides of the equation:

H: 2 on the left, 2 on the right Fe: 2 on the left, 1 on the right O: 3 on the left, 1 on the right

To balance the iron (Fe) atoms, we can place a coefficient of 2 in front of Fe:

H2 + 2 Fe2O3 = 2 Fe + H2O

Now, the equation is balanced with respect to iron. However, the hydrogen (H) atoms are not balanced. To balance them, we can place a coefficient of 3 in front of H2:

3 H2 + 2 Fe2O3 = 2 Fe + 3 H2O

Now, the equation is balanced with respect to both iron and hydrogen.

3. H2S + O2 = SO2 + H2O

Let's count the number of atoms for each element on both sides of the equation:

H: 2 on the left, 2 on the right S: 1 on the left, 1 on the right O: 2 on the left, 3 on the right

To balance the oxygen (O) atoms, we can place a coefficient of 2 in front of H2O:

H2S + O2 = SO2 + 2 H2O

Now, the equation is balanced with respect to oxygen. However, the hydrogen (H) and sulfur (S) atoms are not balanced. To balance them, we can place a coefficient of 2 in front of H2S and SO2:

2 H2S + O2 = 2 SO2 + 2 H2O

Now, the equation is balanced with respect to all elements.

4. H2S + O2 = S + H2O

Let's count the number of atoms for each element on both sides of the equation:

H: 2 on the left, 2 on the right S: 1 on the left, 1 on the right O: 2 on the left, 1 on the right

To balance the oxygen (O) atoms, we can place a coefficient of 2 in front of H2O:

H2S + O2 = S + 2 H2O

Now, the equation is balanced with respect to oxygen. However, the hydrogen (H) and sulfur (S) atoms are not balanced. To balance them, we can place a coefficient of 2 in front of H2S:

2 H2S + O2 = S + 2 H2O

Now, the equation is balanced with respect to all elements.

5. H3N + O2 = N2 + H2O

Let's count the number of atoms for each element on both sides of the equation:

H: 3 on the left, 2 on the right N: 1 on the left, 2 on the right O: 2 on the left, 1 on the right

To balance the hydrogen (H) atoms, we can place a coefficient of 4 in front of H2O:

H3N + O2 = N2 + 4 H2O

Now, the equation is balanced with respect to hydrogen. However, the nitrogen (N) and oxygen (O) atoms are not balanced. To balance them, we can place a coefficient of 2 in front of N2 and O2:

H3N + 2 O2 = 2 N2 + 4 H2O

Now, the equation is balanced with respect to all elements.

6. H3N + O2 = NO + H2O

Let's count the number of atoms for each element on both sides of the equation:

H: 3 on the left, 2 on the right N: 1 on the left, 1 on the right O: 2 on the left, 1 on the right

To balance the hydrogen (H) atoms, we can place a coefficient of 4 in front of H2O:

H3N + O2 = NO + 4 H2O

Now, the equation is balanced with respect to hydrogen. However, the nitrogen (N) and oxygen (O) atoms are not balanced. To balance them, we can place a coefficient of 2 in front of NO:

H3N + O2 = 2 NO + 4 H2O

Now, the equation is balanced with respect to all elements.

I hope this helps! Let me know if you have any further questions.