Question

Вычислите объём бурого газа, который образуется при взаимодействии серебра массой 10,8 г. с раствором концентрированной азотной кислоты массой 100г с массовой долей кислоты 63% при нормальных условиях .

Answer 1

Ответ: 18 дм3

Объяснение:

Ag + 2HNO3 = AgNO3+ NO2 + H2O

1) m(раствора) = m(Ag) + m(HNO3) = 10,8 + 100 = 110,8 г

2) n(HNO3) = m(HNO)/M(HNO3) = 100/63 = 1,6 моль

3) Составим и решим уравнение

n(HNO3)/n(NO2) = 1,6 * x/2 * 1 = 0,8 моль

n(NO2) = 0,8 моль

4) V(NO2) = n(VO2) * Vm = 0,8 * 22,4 = 18 дм3

(плиз, отметь как лучший ответ <3 )

Answer 2

Ответ:

2.24л NO2

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Answer 3

Calculation of the Volume of Brown Gas Produced

To calculate the volume of brown gas produced during the interaction of silver with concentrated nitric acid, we need to determine the number of moles of silver and nitric acid involved in the reaction.

Given: - Mass of silver (Ag) = 10.8 g - Mass of concentrated nitric acid (HNO3) = 100 g - Mass fraction of nitric acid in the solution = 63%

First, let's calculate the number of moles of silver (Ag) using its molar mass (107.87 g/mol):

Number of moles of Ag = (Mass of Ag) / (Molar mass of Ag)

Number of moles of Ag = 10.8 g / 107.87 g/mol

Now, let's calculate the number of moles of nitric acid (HNO3) using its molar mass (63.01 g/mol):

Number of moles of HNO3 = (Mass of HNO3) / (Molar mass of HNO3)

Since the mass of nitric acid is given as 100 g and the mass fraction of nitric acid is 63%, we can calculate the mass of nitric acid in the solution:

Mass of HNO3 = (Mass fraction of HNO3) * (Mass of solution)

Mass of HNO3 = 0.63 * 100 g

Now, we can calculate the number of moles of nitric acid:

Number of moles of HNO3 = (Mass of HNO3) / (Molar mass of HNO3)

Finally, we can determine the volume of brown gas produced using the ideal gas law, assuming normal conditions (1 mole of gas occupies 22.4 liters):

Volume of brown gas = (Number of moles of Ag) * (Volume of 1 mole of gas)

Please note that the specific reaction between silver and concentrated nitric acid was not provided, so the exact stoichiometry of the reaction cannot be determined. Therefore, the volume of brown gas produced cannot be accurately calculated without additional information about the reaction.