Question

Складіть рівняння реакцій за наведеною схемою перетворень: Етин→Бензен→Хлорбензен→Фенол→2,4,6-ТрибромфенолПомогите пожалуйста даю 20 балов.

Answer 1

Ответ:

Объяснение:

1)3C2H2=C6H6(катализатор:активированный уголь);

2)C6H6+Cl2=C6H5Cl+HCl;

3)C6H5Cl+NaOH=C6H5OH+NaCl;

4)C6H5OH +3Br2=C6H2Br3OH+3HBr;

Answer 2

Equation of Reactions for the Given Transformations

The given scheme of transformations involves the conversion of ethyne (also known as acetylene) into benzene, chlorobenzene, phenol, and finally 2,4,6-tribromophenol. Let's break down the reactions step by step:

1. Ethyne to Benzene: - The conversion of ethyne to benzene involves a process called cyclization, where the triple bond in ethyne is converted into a benzene ring. - The reaction is catalyzed by a suitable catalyst, such as palladium or platinum. - The equation for this reaction is:

2 C2H2 → C6H6 [[1]]

2. Benzene to Chlorobenzene: - The conversion of benzene to chlorobenzene involves the substitution of a hydrogen atom in the benzene ring with a chlorine atom. - The reaction is typically carried out using a chlorinating agent, such as chlorine gas (Cl2), or a chlorinating agent in the presence of a Lewis acid catalyst. - The equation for this reaction is:

C6H6 + Cl2 → C6H5Cl + HCl [[2]]

3. Chlorobenzene to Phenol: - The conversion of chlorobenzene to phenol involves the substitution of a chlorine atom in the chlorobenzene ring with a hydroxyl group (-OH). - The reaction is typically carried out using a suitable base, such as sodium hydroxide (NaOH), in the presence of a suitable solvent. - The equation for this reaction is:

C6H5Cl + NaOH → C6H5OH + NaCl [[3]]

4. Phenol to 2,4,6-Tribromophenol: - The conversion of phenol to 2,4,6-tribromophenol involves the substitution of three hydrogen atoms in the phenol ring with three bromine atoms. - The reaction is typically carried out using a brominating agent, such as bromine (Br2), or a brominating agent in the presence of a suitable catalyst. - The equation for this reaction is:

C6H5OH + 3 Br2 → C6H2Br3OH + 3 HBr [[4]]

Therefore, the overall equation for the given scheme of transformations is:

2 C2H2 → C6H6 → C6H5Cl → C6H5OH → C6H2Br3OH