Question

Решение уровнения S->SO2->H2SO3->K2SO3->BaSO3->BaO->BaOH2

Answer 1

S + O2 = SO2↑
SO2 + H2O ⇆ H2SO3
H2SO3 + 2KOH = K2SO3 + 2H2O
K2SO3 + BaCl2 = BaSO3↓ + 2KCl
BaSO3 = BaO + SO2↑
BaO + H2O = Ba(OH)2

Answer 2

Solving the Equation: S -> SO2 -> H2SO3 -> K2SO3 -> BaSO3 -> BaO -> Ba(OH)2

To solve the given equation, we need to determine the products formed at each step of the reaction. Let's break down the equation step by step:

1. S -> SO2: - When sulfur (S) reacts with oxygen (O2), it forms sulfur dioxide (SO2).

2. SO2 -> H2SO3: - Sulfur dioxide (SO2) can react with water (H2O) to form sulfurous acid (H2SO3).

3. H2SO3 -> K2SO3: - Sulfurous acid (H2SO3) can react with potassium hydroxide (KOH) to form potassium sulfite (K2SO3).

4. K2SO3 -> BaSO3: - Potassium sulfite (K2SO3) can react with barium chloride (BaCl2) to form barium sulfite (BaSO3).

5. BaSO3 -> BaO: - Barium sulfite (BaSO3) can be heated to form barium oxide (BaO).

6. BaO -> Ba(OH)2: - Barium oxide (BaO) can react with water (H2O) to form barium hydroxide (Ba(OH)2).

Therefore, the final product of the given equation is Ba(OH)2.

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