Question

Этиленовый углеводород массой 7 г присоединяет 2,24 л бромоводорода. Определите молярную массу и строение этого углеводорода, если известно, что он является цис-изомером

Answer 1

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Answer 2

Molar Mass and Structure of the Ethylene Hydrocarbon

To determine the molar mass and structure of the ethylene hydrocarbon, we can use the given information that it is a cis-isomer and that it reacts with 2.24 L of hydrogen bromide.

Molar Mass Calculation

The molar mass of the ethylene hydrocarbon can be calculated using the reaction with hydrogen bromide. The reaction of ethylene with hydrogen bromide is as follows:

C2H4 + HBr → C2H5Br

From the reaction, we can see that 1 mole of ethylene reacts with 1 mole of hydrogen bromide to produce 1 mole of ethyl bromide. Given that 2.24 L of hydrogen bromide is reacted, we can use the ideal gas law to find the number of moles of hydrogen bromide and then relate it to the number of moles of ethylene.

Using the ideal gas law: PV = nRT

Where: P = pressure V = volume n = number of moles R = ideal gas constant T = temperature

We can rearrange the equation to solve for n: n = PV/RT

Given that the volume (V) is 2.24 L and assuming standard temperature and pressure, we can calculate the number of moles of hydrogen bromide.

Structure of the Ethylene Hydrocarbon

The structure of the ethylene hydrocarbon can be determined based on its molecular formula and the fact that it is a cis-isomer. The molecular formula of ethylene is C2H4, and as a cis-isomer, it means that the two hydrogen atoms are on the same side of the double bond.

Conclusion

By using the given information and the reaction with hydrogen bromide, we can calculate the molar mass of the ethylene hydrocarbon and determine its structure as a cis-isomer with the molecular formula C2H4.