Question

Перетворіть напівсхемиреакцій на хімічні рівняння Al2O3 + H2SO4 = Be(OH)2 + KOH( розчин) = Сума коефіцієнтів у кожному з ріанянь дорівнюватиме відповідно

Answer 1

Al2O3+3H2SO4=Al2(SO4)3+3H2O

1+3+1+3=8

Be(OH)2+2KOH=K2[Be(OH)4]

1+2+1=4

Answer 2

The request you've made involves converting half-reactions into chemical equations. The specific reactions you mentioned are:

1. Al2O3 + H2SO4 2. Be(OH)2 + KOH (solution)

To balance these reactions, we need to ensure that the number of atoms of each element is the same on both sides of the equation and that the total charge is balanced. Here's how you can approach it:

1. For the reaction Al2O3 + H2SO4, you need to balance the aluminum (Al), oxygen (O), and sulfur (S) atoms, as well as the charges. This reaction involves aluminum oxide reacting with sulfuric acid.

2. For the reaction Be(OH)2 + KOH (solution), you need to balance the beryllium (Be), oxygen (O), hydrogen (H), and potassium (K) atoms, as well as the charges. This reaction involves beryllium hydroxide reacting with potassium hydroxide in solution.

Remember, balancing chemical equations requires practice and sometimes trial and error. Make sure to count the atoms of each element on both sides of the equation and adjust the coefficients accordingly to achieve a balanced equation.

If you need further assistance or have specific questions about these reactions, feel free to ask!