Question

Найдите молекулярную формулу спирта в котором массовые доли : углерода -38,7%, водорода -9,7% , кислорода -51,6%

Answer 1

Выходит этиленгликоль, двухосновной спирт

Answer 2

Molecular Formula of Alcohol with Mass Percentages

To determine the molecular formula of the alcohol with the given mass percentages, we need to calculate the empirical formula first. The empirical formula represents the simplest whole number ratio of atoms in a compound.

Given mass percentages: - Carbon (C): 38.7% - Hydrogen (H): 9.7% - Oxygen (O): 51.6%

To calculate the empirical formula, we assume we have 100 grams of the compound. This allows us to convert the mass percentages into grams.

- Carbon (C): 38.7 grams - Hydrogen (H): 9.7 grams - Oxygen (O): 51.6 grams

Next, we need to convert the grams of each element into moles. To do this, we divide the grams by the molar mass of each element.

The molar mass of carbon (C) is approximately 12.01 g/mol. The molar mass of hydrogen (H) is approximately 1.01 g/mol. The molar mass of oxygen (O) is approximately 16.00 g/mol.

Calculating the number of moles for each element:

- Carbon (C): 38.7 g / 12.01 g/mol ≈ 3.22 moles - Hydrogen (H): 9.7 g / 1.01 g/mol ≈ 9.60 moles - Oxygen (O): 51.6 g / 16.00 g/mol ≈ 3.23 moles

Now, we need to find the simplest whole number ratio of the moles. We can do this by dividing each number of moles by the smallest number of moles, which in this case is approximately 3.22 moles.

Dividing the number of moles by 3.22:

- Carbon (C): 3.22 moles / 3.22 ≈ 1 mole - Hydrogen (H): 9.60 moles / 3.22 ≈ 2.99 moles (approximately 3 moles) - Oxygen (O): 3.23 moles / 3.22 ≈ 1 mole

Therefore, the empirical formula of the alcohol with the given mass percentages is CH3O.

Please note that the molecular formula may be a multiple of the empirical formula. To determine the molecular formula, we would need additional information such as the molar mass of the compound.