Question

Написать во йонной формеa). Pb(CH3COO)2+H2S =

Answer 1

Pb(CH₃COO)₂+H₂S = PbS↓ + 2CH₃COOH
Pb²⁺ + 2CH₃COO⁻ + 2H⁺ + S²⁻ = PbS↓ + 2CH₃COO⁻ + 2H⁺
Pb²⁺ + S²⁻ = PbS↓ 

Answer 2

Chemical Reaction in Ionic Form:

The chemical reaction in ionic form for the given reaction Pb(CH3COO)2 + H2S is as follows:

Pb(CH3COO)2 + H2S = PbS + 2CH3COOH This reaction involves lead(II) acetate reacting with hydrogen sulfide to produce lead(II) sulfide and acetic acid.