
По приведённой схеме химического процесса составьте уравнение электронного баланса. Укажите
окислитель и восстановитель. Nano2+K2Cr2O7+H2SO4=NaNo3+Cr2(SO4)4+... KBr+KsO4+KOH=K3AsO4+KBrO3+...

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Chemical Reaction and Electron Balance Equation
The given chemical reaction is: Nano2 + K2Cr2O7 + H2SO4 = NaNo3 + Cr2(SO4)4 + KBr + KsO4 + KOH = K3AsO4 + KBrO3
To balance the chemical equation and determine the electron balance, we need to break down the reaction into two separate reactions and balance each one individually.
1. Balancing the First Reaction: The first reaction is: Nano2 + K2Cr2O7 + H2SO4 = NaNo3 + Cr2(SO4)4
The balanced chemical equation for this reaction is: ``` 10NaNO2 + 6K2Cr2O7 + 7H2SO4 = 10NaNO3 + 3Cr2(SO4)3 + 6K2SO4 + 3H2O ```
To determine the electron balance, we need to calculate the oxidation states of the elements involved in the reaction.
- In the reaction, the oxidation state of chromium changes from +6 in K2Cr2O7 to +3 in Cr2(SO4)3, indicating a reduction. Therefore, K2Cr2O7 is the oxidizing agent (or oxidant), and H2SO4 is the reducing agent (or reductant).
2. Balancing the Second Reaction: The second reaction is: KBr + KsO4 + KOH = K3AsO4 + KBrO3
The balanced chemical equation for this reaction is: ``` 3KBr + 3K2SO4 + 6KOH = 2K3AsO4 + 3KBrO3 + 3H2O ```
In this reaction, the oxidation states of the elements do not change, so there is no electron transfer, and the concept of oxidizing and reducing agents does not apply.
Conclusion
The electron balance equation for the given chemical process involves the reduction of K2Cr2O7 to Cr2(SO4)3 and the oxidation of H2SO4. Additionally, the second reaction does not involve electron transfer.

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