Question

Вычислите массу 56л аммиака,10%-й водный раствор которого в медицине известен под названием "нашатырный спирт"

Answer 1

M(NH3)=n(NH3)*M(NH3)
n=V/Vm=56л/22,4 л= 2,5 моль
m(NH3)=2,5 моль* 17 г/моль= 42,5 (грамм)

Answer 2

Calculation of the Mass of 56L of Ammonia

To calculate the mass of 56L of ammonia, we need to consider that the ammonia is present in a 10% aqueous solution known as "нашатырный спирт" or "spirit of hartshorn" in medicine.

To calculate the mass, we can use the formula:

Mass = Volume x Density

1. First, we need to find the density of the 10% aqueous solution of ammonia. Unfortunately, the search results did not provide the density directly. However, we can make an estimation based on the density of pure ammonia and the fact that the solution is 10% ammonia.

According to source the density of pure ammonia (NH3) is approximately 0.771 g/cm³. Since the solution is 10% ammonia, we can estimate the density of the solution to be around 10% of the density of pure ammonia.

Therefore, the estimated density of the 10% aqueous solution of ammonia is approximately 0.0771 g/cm³.

2. Now, we can calculate the mass using the formula mentioned earlier:

Mass = Volume x Density

Given that the volume is 56L, we need to convert it to cm³ to match the density unit:

1L = 1000 cm³

Therefore, 56L = 56,000 cm³.

Using the estimated density of 0.0771 g/cm³, we can calculate the mass:

Mass = 56,000 cm³ x 0.0771 g/cm³

Calculating this, we find that the mass of 56L of the 10% aqueous solution of ammonia is approximately 4,319.6 grams or 4.32 kilograms.

Please note that this calculation is based on an estimation of the density and may not be entirely accurate. It is always recommended to consult reliable sources or perform laboratory tests for precise measurements.

Conclusion

The mass of 56L of the 10% aqueous solution of ammonia, known as "нашатырный спирт" or "spirit of hartshorn" in medicine, is approximately 4.32 kilograms.