Question

Mr(In(OH)2=Mr(H Cl O4)=​

Answer 1

Ответ:

Mr of In(OH)2 = 118.84 g/mol

Mr of HClO4 = 100.46 g/mol

Answer 2

The molecular weight (Mr) of a compound is calculated by summing the atomic weights of all the atoms in its chemical formula. Let's calculate the molecular weights for In(OH)2 and HClO4:

1. In(OH)2:

• Indium (In) has an atomic weight of approximately 114.82 g/mol.
• Oxygen (O) has an atomic weight of approximately 16.00 g/mol.
• Hydrogen (H) has an atomic weight of approximately 1.01 g/mol.

So, for In(OH)2: Mr(In(OH)2) = (1 * Mr(In)) + (2 * Mr(O)) + (2 * Mr(H)) Mr(In(OH)2) = (1 * 114.82 g/mol) + (2 * 16.00 g/mol) + (2 * 1.01 g/mol) Mr(In(OH)2) = 114.82 g/mol + 32.00 g/mol + 2.02 g/mol Mr(In(OH)2) ≈ 148.84 g/mol

2. HClO4:

• Hydrogen (H) has an atomic weight of approximately 1.01 g/mol.
• Chlorine (Cl) has an atomic weight of approximately 35.45 g/mol.
• Oxygen (O) has an atomic weight of approximately 16.00 g/mol.

So, for HClO4: Mr(HClO4) = (1 * Mr(H)) + (1 * Mr(Cl)) + (4 * Mr(O)) Mr(HClO4) = (1 * 1.01 g/mol) + (1 * 35.45 g/mol) + (4 * 16.00 g/mol) Mr(HClO4) = 1.01 g/mol + 35.45 g/mol + 64.00 g/mol Mr(HClO4) ≈ 100.46 g/mol

Therefore, the molecular weight of In(OH)2 is approximately 148.84 g/mol, and the molecular weight of HClO4 is approximately 100.46 g/mol.