Question

Расставьте коэффициенты в уравнениях реакций, напишите в ионном сокращённом виде 1)K2SO4+BaCl2=BaSO4(осадок)+KCl 2)Na2CO3+HCl=NaCl+H2CO3 3)HNO3+Ag=AgNO3+написать (Газ)+ написать 4)KCl+AgNO3=AgCl(осадок)+KNO3 5)HNO3+CuO=Cu(NO3)2+H20

Answer 1

1)K2SO4+BaCl2=BaSO4(осадок)+2KCl

Ba(2+)+SO4(2-)=BaSO4(осадок)

2)Na2CO3+2HCl=2NaCl+H2O+CO2

CO3(2-)+2H(+)=CO2+H2O

3)3HNO3+3Ag=3AgNO3+NO+2H2O
4)KCl+AgNO3=AgCl(осадок)+KNO3
Ag(+)+Cl(-)=AgCl(осадок)
5)2HNO3+CuO=Cu(NO3)2+H2O
2H(+)+CuO=Cu(2+)+H2O

Answer 2

K2SO4+BaCL2-->BaSO4+2KCL
2K⁺+SO⁻²₄+Ba⁺²+2CL⁻-->BaSO4+2K⁺+2CL⁻
SO⁻²₄+Ba⁺²-->BaSO4

Na2CO3+2HCl-->2NaCl+H2O+CO2
2Na⁺+CO⁻²₃+2H⁺+2CL⁻-->2Na⁺+2CL⁻+H2O+CO2
CO⁻²₃+2H⁺-->H2O+CO₂

4HNO3+3Ag-->3AgNO3+NO+3H2O
4H⁺+4NO⁻₃+3Ag⁰-->3Ag⁺+3NO⁻₃+NO+3H2O

KCl+AgNO3-->AgCl↓+KNO3
K⁺+C⁻L+Ag⁺+NO⁻₃-->AgCL↓+K⁺+NO⁻₃
CL⁻+Ag⁺-->AgCL

2HNO3+CuO-->Cu(NO3)2+H20
2H⁺+2NO⁻₃+CuO-->Cu⁺²+2NO⁻₃+H2O
2H⁺+CuO-->Cu²⁺+H2O

Answer 3

Balancing Chemical Equations and Ion Notation

Let's work through the chemical equations you've provided and balance them, as well as write them in ionic shorthand notation.

1) K2SO4 + BaCl2 = BaSO4 + KCl First, let's balance the equation: - The balanced equation is: K2SO4 + BaCl2 = BaSO4 + 2KCl Now, let's write the equation in ionic shorthand notation: - 2K^+ + SO4^2- + Ba^2+ + 2Cl^- = BaSO4(s) + 2K^+ + 2Cl^-

2) Na2CO3 + 2HCl = 2NaCl + H2CO3 Balancing the equation: - The balanced equation is: Na2CO3 + 2HCl = 2NaCl + H2CO3 Writing the equation in ionic shorthand notation: - 2Na^+ + CO3^2- + 2H^+ + 2Cl^- = 2Na^+ + 2Cl^- + H2CO3

3) HNO3 + Ag = AgNO3 + H2 Balancing the equation: - The balanced equation is: 3HNO3 + Ag = AgNO3 + NO2 + H2O Writing the equation in ionic shorthand notation: - 3H^+ + 3NO3^- + Ag = Ag^+ + NO3^- + NO2 + H2O

4) KCl + AgNO3 = AgCl + KNO3 Balancing the equation: - The balanced equation is: KCl + AgNO3 = AgCl + KNO3 Writing the equation in ionic shorthand notation: - K^+ + Cl^- + Ag^+ + NO3^- = AgCl(s) + K^+ + NO3^-

5) HNO3 + CuO = Cu(NO3)2 + H2O Balancing the equation: - The balanced equation is: 4HNO3 + CuO = Cu(NO3)2 + 2H2O Writing the equation in ionic shorthand notation: - 4H^+ + 4NO3^- + Cu^2+ + O^2- = Cu^2+ + 2NO3^- + 2H2O

I hope this helps! If you have any more questions or need further assistance, feel free to ask.