Question

Термохимическое уравнения горения водорода 2H2(Г)+O2(Г)=2H2O(Ж)+484 Кдж.при сгорании 2.24л водорода в избытке кислорода сколько выделится теплоты решите!!!

Answer 1

Ну уравнение в начале:

2H2 + O2 = 2H2O + 484 кДж

1) Рассчитаем количесвто вещества 2,24 моль водорода:

n=V/Vm = 2,24л/22,4л/моль = 0,1 моль

2) По уравнению реакции, горит 2 моль водорода, найдем массу этих двух моль водорода:

m=n*M=2моль*2г/моль=4грамма

3) Раасчитаем массу 0,1 моль водорода:

0,1моль*2г/моль = 0,2 грамма

4) Составим пропорцию:

4 грамма -> 484 кДж

0.2 грамма -> х кДж

Решаем эту пропорцию и получаем:

х = 24,2 кДж

Ответ: ...  

 

Answer 2

Calculation of Heat Released during the Combustion of Hydrogen

To calculate the amount of heat released during the combustion of hydrogen, we can use the given thermochemical equation:

2H2(g) + O2(g) -> 2H2O(l) + 484 kJ

We are given that 2.24 L of hydrogen is burned in excess oxygen.

To solve this problem, we need to convert the volume of hydrogen gas to moles using the ideal gas law. The molar volume of any gas at standard temperature and pressure (STP) is 22.4 L/mol.

Let's calculate the number of moles of hydrogen:

Step 1: Convert the volume of hydrogen gas to moles using the ideal gas law:

n = V / Vm

where: n = number of moles V = volume of hydrogen gas (2.24 L) Vm = molar volume of hydrogen gas at STP (22.4 L/mol)

n = 2.24 L / 22.4 L/mol n = 0.1 mol

Step 2: Use the stoichiometry of the balanced equation to determine the amount of heat released:

From the balanced equation, we can see that 2 moles of hydrogen gas produce 2 moles of water and release 484 kJ of heat.

Since we have 0.1 mol of hydrogen gas, we can calculate the amount of heat released using a proportion:

(0.1 mol H2) / (2 mol H2) = x / 484 kJ

x = (0.1 mol H2) * (484 kJ) / (2 mol H2) x = 24.2 kJ

Therefore, when 2.24 L of hydrogen gas is burned in excess oxygen, approximately 24.2 kJ of heat is released.

Please let me know if you need any further assistance!